All categories

2 years ago

How much of the total energy in Problem 3 and 4 has been transformed to kinetic energy?

Physics

1 answer:

ale4655 [162]2 years ago

6 0

I am only a HS Freshman so I might be wrong

Answer:

3. Its potential energy and the formula for PE = mgh so you would use the weight given (Weight = mg) and mg is in the (Potential Energy) forumula so we multiply 3 by 30 and get 90 Joules

4. We would do the same thing with this: PE = mgh; PE = 10*3 = 30 Joules

Once again I am only a Freshman and I have taken Private AP Physics classes so just maybe wait for someone who is more confident.

This is just what I would answer

btw, for problem 5, the fromula for kinetic energy is 1/2*m*v^2

You might be interested in

A firewoman dropped a person onto the safety net. Right before the person hit the net he had a

sergejj [24]

Answer:

The Mass of a person is calculated to be 28.6kg .

Explanation:

This is based on Kinetic energy and we know, that Kinetic energy is the energy possessed by body by virtue of its motion .

It can be calculated by expression :

K.E=1/2mv²

Velocity of a person = 11.2m/sec

Kinetic energy = 1800J

Mass of person = ?

We know ,

K.E=1/2mv²

so, putting values we have :

1800=1/2 x m x (11.2)²

That is ,

m=1800 x 2 /11.2 x 11.2

m=3600/125.44

m = 28.6 kg

6 0

3 years ago

An electron is released from rest at the negative plate of a parallel plate capacitor. The charge per unit area on each plate is

Andreas93 [3]

Answer:

$v=1.08\times 10^7\ m/s$

Explanation:

Initial speed of the electron, u = 0

The charge per unit area of each plate, $\dfrac{Q}{A}=1.69\times 10^{-7}\ C/m^2$

Separation between the plates, $d=1.75\times 10^{-2}\ m$

An electron is released from rest, u = 0

Using equation of kinematics,

$v^2-u^2=2ad$ ..........(1)

Acceleration of the electron in electric field, $a=\dfrac{qE}{m}$ ............(2)

Electric field, $E=\dfrac{\sigma}{\epsilon_o}$ ............(3)

From equation (1), (2) and (3) :

$v=\sqrt{\dfrac{2q\sigma d}{m\epsilon_o}}$

$v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\times 1.69\times 10^{-7}\times 1.75\times 10^{-2}}{9.1\times 10^{-31}\times 8.85\times 10^{-12}}}$

v = 10840393.1799 m/s

$v=1.08\times 10^7\ m/s$

So, the electron is moving with a speed of $1.08\times 10^7\ m/s$ before it reaches the positive plate. Hence, this is the required solution.

3 0

3 years ago

Rahim is watching his favorite football team on television. In order to work, the television must be

kvasek [131]

Answer:

it would be the cord will have the most energy at the moment.

Explanation:

...

3 0

2 years ago

Physics is really confusing...is there anyone that can show it to me?

coldgirl [10]

Answer:

1.0×10³ N

Explanation:

μs is the static coefficient of friction. That's the friction that acts on a stationary (non-moving) object when being pushed or pulled.

μk is the kinetic coefficient of friction. That's the friction that acts on a moving object.

To budge the pig (while it's still stationary), we need to overcome the static friction.

F = N μs

For a non-moving object on level ground, the normal force N equals the weight.

F = mg μs

Given m = 130 kg and μs = 0.80:

F = (130 kg) (9.8 m/s²) (0.80)

F = 1019.2 N

Rounded to two significant figures, the force needed to budge the pig is 1.0×10³ N.

3 0

3 years ago

Listening to your stereo system while driving can be dangerous because:

kotegsom [21]

Hey there!

They answer is option C music would make it harder to focus on the road.

Hope this helps.

6 0

2 years ago

Read 2 more answers