Question

In principle, when you fire a rifle, the recoil should push you backward. How big a push will it give? Let's find out by doing a calculation in a very artificial situation. Suppose a man standing on frictionless ice fires a rifle horizontally. The mass of the man together with the rifle is 70 kg, and the mass of the bullet is 10 g.

Answer 1

Answer:

$v= \frac{10\times10^{-3} V}{70}$ m/s

Explanation:

Assumption: bullet leaves the muzzle at a speed of V m/s

and velocity of push received by the man be v m/s

According to newton's third law to every action there is always an equal and opposite reaction.

therefore,

mass of man× velocity = mass of bullet×its velocity

⇒70×v= 10×10^-3 ×V

solving the above eqaution we get

therefore $v= \frac{10\times10^{-3} V}{70}$ m/s