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beks73 [17]
3 years ago
6

In principle, when you fire a rifle, the recoil should push you backward. How big a push will it give? Let's find out by doing a

calculation in a very artificial situation. Suppose a man standing on frictionless ice fires a rifle horizontally. The mass of the man together with the rifle is 70 kg, and the mass of the bullet is 10 g.
Physics
1 answer:
MaRussiya [10]3 years ago
7 0

Answer:

v= \frac{10\times10^{-3} V}{70} m/s

Explanation:

Assumption: bullet leaves the muzzle at a speed of V m/s

and velocity of push received by the man be v m/s

According to newton's third law to every action there is always an equal and opposite reaction.

therefore,

mass of man× velocity = mass of bullet×its velocity

⇒70×v= 10×10^-3 ×V

solving the above eqaution we get

therefore v= \frac{10\times10^{-3} V}{70} m/s

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Consider the circuit shown in the figure below. (Let R1 = 3.00 Ω, R2 = 8.00 Ω, and = 10.0 V.). . (a) Find the voltage across R1.
Goryan [66]
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A tennis ball is released from a height of 4.0 m above the floor. After its third bounce off the floor, it reaches a height of 1
diamong [38]

Answer:

The percentage of its mechanical energy does the ball lose with each bounce is 23 %

Explanation:

Given data,

The tennis ball is released from the height, h = 4 m

After the third bounce it reaches height, h' = 183 cm

                                                                       = 1.83 m

The total mechanical energy of the ball is equal to its maximum P.E

                                      E = mgh

                                          = 4 mg

At height h', the P.E becomes

                                      E' = mgh'

                                           = 1.83 mg

The percentage of change in energy the ball retains to its original energy,

                                 \Delta E\%=\frac{1.83mg}{4mg}\times100\%

                                  ΔE % = 45 %

The ball retains only the 45% of its original energy after 3 bounces.

Therefore, the energy retains in each bounce is

                                   ∛ (0.45) = 0.77

The ball retains only the 77% of its original energy.

The energy lost to the floor is,

                                E = 100 - 77

                                   = 23 %

Hence, the percentage of its mechanical energy does the ball lose with each bounce is 23 %      

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