3 years ago

Why does life hate me?

Physics

2 answers:

yKpoI14uk [10]3 years ago

6 0

Answer:

felt that

Explanation:

Julli [10]3 years ago

5 0

More like why do you hate life:/

You might be interested in

Someone please help me

schepotkina [342]

The answer is oil and water. If you want I could give you the reason too

5 0

3 years ago

Read 2 more answers

Why is it harder to breathe on a

Law Incorporation [45]

I think it’s d but I’m not sure

6 0

3 years ago

PLEASE HELP! Please get these right

umka2103 [35]

Green. This is because chlorophyll reflects the color green, which is why we see it as this color.

7 0

3 years ago

Heat of ______ is the energy needed for a substance to change from a liquid to a gas

marusya05 [52]

Answer:

Heat of vaporization

Explanation:

When water is at high levels of temperature heat is move as an energy source into the air.

3 0

3 years ago

Read 2 more answers

A point charge of -0.70 μC is fixed to one corner of a square. An identical charge is fixed to the diagonally opposite corner. A

MakcuM [25]

Answer:

The magnitude and algebraic sign of q is $14\sqrt{2}\ \mu C$

Explanation:

Given that,

Point charge = -0.70 μC[/tex]

We need to calculate the force for all charges

The electric force at first corner

$F_{1}=\dfrac{-k0.70\times10^{-6}q}{r^2}$

The electric force at opposite corner

$F_{3}=\dfrac{-k0.70\times10^{-6}q}{r^2}$

The net force is

$F=\sqrt{F_{1}^2+F_{2}^2}$

Put the value into the formula

$F=\sqrt{(\dfrac{-k0.70\times10^{-6}q}{r^2})^2+(\dfrac{-k0.70\times10^{-6}q}{r^2})^2}$

The electric force at second corner

$F_{2}=\dfrac{-kq^2}{2r^2}$

The net force acting on either of the charges is zero.

So, $F=F'$

$\sqrt{(\dfrac{k0.70\times10^{-6}q}{r^2})^2+(\dfrac{-k0.70\times10^{-6}q}{r^2})^2}=\dfrac{kq^2}{2r^2}$

$\sqrt{2}\times\dfrac{0.70\times10^{-6}kq}{r^2}=\dfrac{kq^2}{2r^2}$

$q=14\sqrt{2}\ \mu C$

Hence, The magnitude and algebraic sign of q is $14\sqrt{2}\ \mu C$

8 0

3 years ago