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DaniilM [7]
3 years ago
6

What is the purpose of the remote desktop easy print driver?

Computers and Technology
1 answer:
Georgia [21]3 years ago
6 0
<span>Easy Print allows remote clients to print to local print devices via a print redirector.</span>
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What is the last step in planning your budget
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To print a range of cells in the active worksheet, click___ in the settings in print gallery.
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<span>print entire workbook</span>
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3 years ago
Write a program that asks the user to enter the amount s/he has budgeted for a month. The amount should be between 1000 and 2000
Elena-2011 [213]

Answer:

The program to this question can be given as:

Program:

  //import package for user input.

import java.util.*;      

//define class

public class Budget                      

{

public static void main(String [] a)            //define main method.

{

//creating Scanner class object.

Scanner ob =new Scanner(System.in);    

//define variable.      

double budgetamount=0, amountspent=0 ,difference=0,total=0,num=0 ;        

int count = 0;                            

System.out.println("How much have you budgeted for the month? :");        //print message.

budgetamount=ob.nextDouble();                             //taking input

       while(budgetamount != 0)           //checkig number greater then 4 digite.

       {

           budgetamount= budgetamount/10;        

           ++count;

       }

       if(count>4)                 //condition

       {

       System.out.println("enter each expense, then type -999 to quit: ");

       while(num!=-999)               //taking expense  

       {

       total=total+num;                 //totaling expense

       num=scan.nextDouble();                  

       }

       if(total<=budgetamount)           //condtion for over budget.

       {

       System.out.print("under budget:");         //print message

       System.out.print(budgetamount-total);

       }

       else

       {

       System.out.print("over budget:");              //for under budget

       System.out.print(total-budgetamount);

       }

       }

       else

       {

       System.out.println("not valid");        //message for number lessthen 4 digit.    

       }                                      

}

}

output:

How much have you budgeted for the month? : 1200.55.

enter each expense, then type -999 to quit: 365.89

556.90

339.98

-999

over budget:1262.77

Explanation:

The explanation of this program can be given as:

In the above program we import the package in that is used for scanner class. This class is used for the input from the user after input we use the while loop and if-else statement. The while loop is the entry control loop It is used for input validation and if-else is used for the checking condition. Then we insert expense that is inserted by the user. Then we calculate under-budgeted and over-budgeted by conditional statement that is if-else. and at the last we print it.

5 0
3 years ago
Having reviewed dod wireless stig (ver6, release 1), sarah learns she may only utilize secnet 54 and ______________ for transmit
xeze [42]
<span>Sarah learns she may only utilize SecNet 54 and SecNet 11 for transmitting classified information up to top secret.
</span>

SecNet 11 Plus is a family of encrypted <span>802.11b wi-fi <span>networking products. The Army has also approved</span></span> SecNet 11<span> as part of the classified Navy Marine Corps Intranet (NMCI) wireless solution. There are many products in SecNet 11 family, such as SecNet 11 Plus PC card, the SecNet 11 Wireless ridge, and the SecNet 11 Key Fill Cable etc.</span>

7 0
3 years ago
A researcher plans to identify each participant in a certain medical experiment with a code consisting of either a single letter
trapecia [35]

Answer:

5 Letters

Explanation:

So we need 12 distinct codes made of a single letter or a pair of letters.

What would be the least number of letters?

Lets try with 3 letters A, B and C

The possible combinations are: A, B, C, AB, AC, BC

These are 6 codes and we need 12 so lets try more A, B, C and D

The possible combinations are: A, B, C, D, AB, AC, AD, BC, BD, CD

These are 10 codes and we need 12 so lets try more A, B, C, D and E

The possible combinations are:

A, B, C, D, E, AB, AC, AD, AE, BC, BD, BE, CD, CE, DE

Finally we got 15 distinct codes which are more than 12 so the least number of letters needed are 5.

Using formula:

Four letters = 4C1 + 4C2 = 4 + 6 = 10

Five letters = 5C1 + 5C2 = 5 + 10 = 15

5 0
2 years ago
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