Find the vertex of: y=6(x-1)2-8 (x,y)

1 answer:

5 0

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
y=a(x-{{ h}})^2+{{ k}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-----------------------------\\\\
\begin{array}{lllcll}
y=&6(x-&1)^2&-8\\
&\uparrow &\uparrow &\uparrow \\
&a&h&k
\end{array}$

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