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mojhsa [17]
3 years ago
13

Brandi is half as old as candi. Randy is 10 years older than brandi.if candi is 22, how old is randy

Mathematics
1 answer:
seraphim [82]3 years ago
6 0
22 divided by 2 = 11
11+10=21
The answer is 21
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Write the number in 2 equivalent forms as a fraction, decimal, or percent.
hjlf

Answer:

96% percent and fraction is 24/25

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3 years ago
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Identify the graphical solution to the inequality
NeTakaya

Answer:

A

Step-by-step explanation:

to solve absolute value inequalities you must solve it for when the absolute value is positive and then when it is negative

example, |4| = 4 and -4

first solution will be when we're solving for the positive value:

+(-4x+7) ≥ 27

-4x + 7 ≥ 27

-4x ≥ 20

x ≤ -5   [reverse the symbol when mult or div by a negative]

-(-4x+7) ≥ 27

4x - 7 ≥ 27

4x ≥ 34

x ≥ 34/4 or x ≥ 8 1/2

solution:  x ≤ -5 or x ≥ 8.5

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3 years ago
You are a traffic accident investigator. You have arrived at the scene of an accident. Two trucks of equal mass (3,000 kg each)
Kazeer [188]

Answer:

1) Kinetic energy of the truck 1 is 600,000 joules.

Kinetic energy of the truck 2 is 1,837,500 joules.

2 a)Potential energy of truck 1 is 646,800 Joules.

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

Step-by-step explanation:

Mass of the truck 1 and truck 2,m = 3000 kg

Velocity of the truck 1, v_1 = = 20 m./s

Velocity of the truck 2,v_2 = 35 m./s

1. Kinetic energy of the truck 1:\frac{1}{2}mv_{1}^2=\frac{1}{2}\times 3000 kg\times (20 m/s)^=600,000 joules

Kinetic energy of the truck 2:\frac{1}{2}mv_{2}^2=\frac{1}{2}\times 3000 kg\times (35 m/s)^=1,837,500 joules

2.a) Energy loose by the truck 1:

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At that height potential energy will be maximum:

Potential energy of truck 1 at that height = mgh=3000\times 9.8 m/s^2\times 22 m=646,800 Joules

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

3 0
3 years ago
What is equivalent to 2/4
padilas [110]
1/2, 4/8, etc. Because they all equal to one half. <span />
8 0
3 years ago
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How do I factor x^4-5x^2+6?
Vilka [71]

Answer:

=(x^2-3)(x^2-2)

Step-by-step explanation:

So we have the expression:

x^4-5x^2+6

And we wish to factor it.

First, let's make a substitution. Let's let u be equal to x². Therefore, our expression is now:

=u^2-5u+6

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We can use the numbers -3 and -2. So:

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For the last two terms, factor out a -3. So:

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Grouping:

=(u-3)(u-2)

Now, substitute back the x² for u:

=(x^2-3)(x^2-2)

And this is the simplest form.

And we're done!

3 0
3 years ago
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