Let AB extended intersect DC extended at point E
<span>We now have right triangle BEC with E = 90 degrees </span>
<span>For triangle BEC: </span>
<span>Exterior angle at E = 90 </span>
<span>Exterior angle at C = 148 (given) </span>
<span>Exterior angle of all polygons add up to 360 degrees </span>
<span>Exterior angle at B = 360−148−90 = 122 </span>
<span>So in quadrilateral ABCD </span>
<span>B = 122 </span>
<span>D = 360−44−148−122 = 46</span>
Answer:
y= -x - 10
Step-by-step explanation:
provided in photo
The answer to this question is 5x3-3x2-5x+3
Step-by-step explanation:
f(x)+g(x)=(2x^2 + 5x +6) + (3x^2 +4x - 10)
Combine like terms
5x^2 + 9x -4
f(x)-g(x)=(2x^2 + 5x +6) - (3x^2 +4x - 10)
Distribute the negative
(2x^2 + 5x +6) + (-3x^2 -4x + 10)
Combine like terms
-x^2 +x +16
Answer:D
Step-by-step explanation:
