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dedylja [7]
3 years ago
15

What is the freezing point of an aqueous solution that boils at 103.7 degrees Celsius?

Chemistry
1 answer:
inna [77]3 years ago
7 0
For this, we use equations from the colligative properties of solutions specifically boiling point elevation and freezing point depression. The equations for these are expressed as:

ΔTb = kb m

where k is a boiling point elevation constant and m is the concentration in terms of molality

ΔTf = kf m 

where k is a freezing point elevation <span>constant and m is the concentration in terms of molality
</span>
We use both expression to solve for the freezing point. For this case, concentration is the same. The equation will then be:

ΔTf = kf ( ΔTb / kb )
0-Tf = 1.86 (103.7 - 100 / 0.512 )
Tf = -13.4°C
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