It’s 34 I had this question
Answer:
oK so pay pattention to the fractions
Explanation:
Answer : The concentration of 
at equilibrium is 0 M.
Solution : Given,
Concentration of = 0.0200 M
Concentration of 
= 1.00 M
The given equilibrium reaction is,
![Fe^{3+}(aq)+3C_2O_4^{2-}(aq)\rightleftharpoons [Fe(C_2O_4)_3]^{3-}(aq)](https://tex.z-dn.net/?f=Fe%5E%7B3%2B%7D%28aq%29%2B3C_2O_4%5E%7B2-%7D%28aq%29%5Crightleftharpoons%20%5BFe%28C_2O_4%29_3%5D%5E%7B3-%7D%28aq%29)
Initially conc. 0.02 1.00 0
At eqm. (0.02-x) (1.00-3x) x
The expression of 
will be,
![K_c=\frac{[[Fe(C_2O_4)_3]^{3-}]}{[C_2O_4^{2-}]^3[Fe^{3+}]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5B%5BFe%28C_2O_4%29_3%5D%5E%7B3-%7D%5D%7D%7B%5BC_2O_4%5E%7B2-%7D%5D%5E3%5BFe%5E%7B3%2B%7D%5D%7D)
By solving the term, we get:
Concentration of at equilibrium = 0.02 - x = 0.02 - 0.02 = 0 M
Therefore, the concentration of at equilibrium is 0 M.
Answer:
B. Nonpolar covalent bond
Explanation:
Between two Nitrogen atoms, a non-polar covalent bond would be formed.
So, what is the nature of a covalent bond, and what makes a covalent bond non-polar?
A covalent bond is a type of bond that forms between two atoms that shares their valence electrons. The valence electrons are donated by the two atoms and they are shared in order to achieve an octet. This bond type is predominantly between atoms that have an electronegativity difference less than 0.5. Using the electronegativity values, we see that a difference of 0 would be obtained.
Due to equal affinities of the two atoms for the valence electrons, none of them will pull the electrons closer to themselves. There won't be any form of charge separation on the two atoms and a Nitrogen molecule will form. This makes the bond type a non-polar covalent type.
