(9^x) - 3 = 2*3^x
(9^x) - 3 - (2*3^x) = (2*3^x) - (2*3^x)
(9^x) - (2*3^x) - 3 = 0
(3^2)^x - 2*(3^x) - 3 = 0
3^(2x) - 2*(3^x) - 3 = 0
3^(x*2) - 2*(3^x) - 3 = 0
(3^x)^2 - 2*(3^x) - 3 = 0
z^2 - 2*z - 3 = 0 ............ let z = 3^x
(z - 3)(z + 1) = 0
If z-3 = 0, then z = 3 when we isolate z
If z = 3, and z = 3^x, then
z = 3
3^x = 3
3^x = 3^1
x = 1
which is a solutin in terms of x
If z+1 = 0 then z = -1
If z = -1 and z = 3^x, then there are NO solutions for this part of the equation
The quantity 3^x is never negative no matter what the x value is
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Answer: x = 1
The answer is a because 4+3 =7 half plus quarter equals three quarters 11 -7 and three quarters equals A
The ratio adults to students is 1:6
Multiply both sides by 60 so that the right side is 360 and it is
60:360
Therefore there needs to be 60 adults which is option D
Hope this helps :)
Answer:
Step-by-step explanation:
Cost of toy =100
Selling price = 90
Loss = 100
Loss in percentage = 10/90*100
Loss in %= 11.11