The equation of direct variation is,
Substitute the values of <em>y</em> and <em>x</em>.
So, the obtained equation will be <em>y</em>=1.35(x).
Let's check with the values of <em>x</em>.
1) If <em>x</em>=4
2) If <em>x</em>=2
3) If <em>x</em>=-2
F: R → R is given by, f(x) = [x]
It is seen that f(1.2) = [1.2] = 1, f(1.9) = [1.9] = 1
So, f(1.2) = f(1.9), but 1.2 ≠ 1.9
f is not one-one
Now, consider 0.7 ε R
It is known that f(x) = [x] is always an integer. Thus, there does not exist any element x ε R such that f(x) = 0.7
So, f is not onto
Hence, the greatest integer function is neither one-one nor onto.
The answer was quite complicated but I hope it will help you.
Answer:
if donuts are 2 for each and cookies for 1 each it could be
X x 2 and X x 1
one equation could be 4 donuts for 2$ and 7 cookies for 1$
C
The numbers on the left represent 10 times that number
The numbers on the right are added to the end of the number on the left so
3I1=31 and 4I8=48 and 3I 1 1 2= 31 31 32
Answer:
therefore f(x)=100x-5-1 has an x-intercept
