Question

Write the equation of a line passing through (-4.3) and perpendicular to -6x + 4y =-12.

Answer 1

Answer:

y=-2/3*x+1/3

Step-by-step explanation:

-6x+4y=-12

put into y=mx+b line equation

4y=6x-12

y=(6/4)x-(12/4)

y=(3/2)x-4

slope is 3/2

to find perpendiular line slope take the negative inverse.

-(2/3) = slope of perpendicular line

use line equation and solve for y-intercept (b)

3=(-2/3)*(-4)+b

3=8/3+b

b= 9/3-8/3 = 1/3 : 3 = 9/3 to allow for subrtaction of fractions.