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Paul [167]
3 years ago
7

Write the equation of a line passing through (-4.3) and perpendicular to -6x + 4y =-12.

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
3 0

Answer:

y=-2/3*x+1/3

Step-by-step explanation:

-6x+4y=-12

put into y=mx+b line equation

4y=6x-12

y=(6/4)x-(12/4)

y=(3/2)x-4

slope is 3/2

to find perpendiular line slope take the negative inverse.

-(2/3) = slope of perpendicular line

use line equation and solve for y-intercept (b)

3=(-2/3)*(-4)+b

3=8/3+b

b= 9/3-8/3 = 1/3 : 3 = 9/3 to allow for subrtaction of fractions.

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Answer:

<em>Proof below</em>

Step-by-step explanation:

<u>Right Triangles</u>

In any right triangle, i.e., where one of its internal angles is 90°, some interesting relations stand. One of the most-used is Pythagora's Theorem.

In a right triangle with shorter sides a and b, and longest side c, called the hypotenuse, the following equation is satisfied:

c^2=a^2+b^2

The image provided in the question shows a line passing through points A(0,4) and B(3,0) that forms a right triangle with both axes.

The origin is marked as C(0,0) and the point M is the midpoint of the segment AB. We have to prove.

CM=\frac{1}{2}AB

First, find the coordinates of the midpoint M(xm,ym):

\displaystyle x_m=\frac{0+3}{2}=1.5

\displaystyle y_m=\frac{4+0}{2}=2

Thus, the midpoint is M( 1.5 , 2 )

Calculate the distance CM:

CM=\sqrt{(1.5-0)^2+(2-0)^2}

CM=\sqrt{2.25+4}=\sqrt{6.25}=2.5

CM=2.5

Now find the distance AB:

AB=\sqrt{(3-0)^2+(4-0)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}

AB=5

AB/2=2.5

It's proven CM is half of AB

3 0
3 years ago
11/16 on a number line that goes from 0-2
Dafna11 [192]

Answer:

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7 0
2 years ago
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xeze [42]
Consider, pls, this option:
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9514 1404 393

Answer:

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Step-by-step explanation:

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5 0
2 years ago
Read 2 more answers
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hichkok12 [17]
Answer: A.
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(REFER TO CHART BELOW)

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