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Irina-Kira [14]

3 years ago

12

A 68.4-g sample of potassium chloride was added to 200.0 g of water at 20oC. Is the solution saturated, unsaturated, or supersat

urated? Use Figure 8-2 to answer this question.

1 answer:

eduard3 years ago

7 0

I'm pretty sure it would be saturated.

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Not only did Skid get shot out of a cannon when he was a clown in the circus, but he was also launched into the air by a vertica

tiny-mole [99]

Answer:

v = 16.11 m / s

Explanation:

For this exercise we must use the principle of conservation of energy. We set a reference system on the part of the platform without elongation

starting point. When the spring is compressed

Em₀ = K_e + U = ½ k x² + m g x ’

final point. The point where it leaves the platform

Em_f = K = ½ m v²

energy is conserved

Em₀ = Em_f

½ k x² + m g x ’= ½ m v²

v² = $\frac{k}{m}$ x² + g x

let's calculate

v² = $\frac{8700}{55}$ 1.25² + 9.8 1.25

v² = 247.159 + 12.25 = 259.409

v = 16.11 m / s

8 0

3 years ago

An object moves in a straight path. Its position x as a function of time t is presented by the equation x(t) = at – bt2+c, where

ankoles [38]

Answer:

The answer is below

Explanation:

Given that:

x(t) = at – bt2+c

a) x(t) = at – bt2+c

Substituting a = 1.4 m/s, b = 0.06 m/s2 and c =50 m gives:

x(t) = 1.4t - 0.06t² + 50

At t = 5, x(5) = 1.4(5) - 0.06(5)² + 50 = 55.5 m

At t = 0, x(0) = 1.4(0) - 0.06(0)² + 50 = 50 m

The average velocity (v) is given as:

$v=\frac{x(5)-x(0)}{5-0}\\ \\v=\frac{55.5-50}{5-0}=1.1\\ \\v=1.1\ m/s$

b) x(t) = 1.4t - 0.06t² + 50

At t = 10, x(10) = 1.4(10) - 0.06(10)² + 50 = 58 m

At t = 0, x(0) = 1.4(0) - 0.06(0)² + 50 = 50 m

The average velocity (v) is given as:

$v=\frac{x(10)-x(0)}{10-0}\\ \\v=\frac{58-50}{10-0}=0.8\\ \\v=0.8\ m/s$

c) x(t) = 1.4t - 0.06t² + 50

At t = 15, x(5) = 1.4(15) - 0.06(15)² + 50 = 57.5 m

At t = 10, x(10) = 1.4(10) - 0.06(10)² + 50 = 58 m

The average velocity (v) is given as:

$v=\frac{x(15)-x(10)}{15-10}\\ \\v=\frac{57.5-58}{15-10}=0.1\\ \\v=0.1\ m/s$

6 0

3 years ago

Gravity and Electromagnetic force

Sladkaya [172]

Differences between gravitational and electromagnetic radiation

So far we have been emphasizing how, at a fundamental level, the generation and propagation of gravitational and electromagnetic radiation are basically quite similar. This is a major point in demystifying gravitational waves. But, on a more practical level, gravitational and electromagnetic waves are quite different: we see and use electromagnetic waves every day, while we have yet to make a confirmed direct detection of gravitational waves (which is why they seemed so mysterious in the first place).

There are two principal differences between gravity and electromagnetism, each with its own set of consequences for the nature and information content of its radiation, as described below.

<span><span><span>Gravity is a weak force, but has only one sign of charge.
Electromagnetism is much stronger, but comes in two opposing signs of charge.</span>
This is the most significant difference between gravity and electromagnetism, and is the main reason why we perceive these two phenomena so differently. It has several immediate consequences:<span>Significant gravitational fields are generated by accumulating bulk concentrations of matter. Electromagnetic fields are generated by slight imbalances caused by small (often microscopic) separations of charge.<span>Gravitational waves, similarly, are generated by the bulk motion of large masses, and will have wavelengths much longer than the objects themselves. Electromagnetic waves, meanwhile, are typically generated by small movements of charge pairs within objects, and have wavelengths much smaller than the objects themselves.</span><span>Gravitational waves are weakly interacting, making them extraordinarily difficult to detect; at the same time, they can travel unhindered through intervening matter of any density or composition. Electromagnetic waves are strongly interacting with normal matter, making them easy to detect; but they are readily absorbed or scattered by intervening matter.

</span><span>Gravitational waves give holistic, sound-like information about the overall motions and vibrations of objects. Electromagnetic waves give images representing the aggregate properties of microscopic charges at the surfaces of objects.</span></span>
</span><span><span>Gravitational charge is equivalent to inertia.
Electromagnetic charge is unrelated to inertia. </span>
This is the more fundamental difference between electromagnetism and gravity, and influences many of the details of gravitational radiation, but in itself is not responsible for the dramatic differences in how we perceive these two types of radiation. Most of the consequences of the principle of equivalence in gravity have already be discussed, such as:<span><span>The fundamental field of gravity is a gravitational force gradient (or tidal) field, and requires an apparatus spread out over some distance in order to detect it. The fundamental field in electromagnetism is an electric force field, which can be felt by individual charges within an apparatus.</span><span>The dominant mode of gravitational radiation is quadrupolar: it has a quadratic dependence on the positions of the generating charges, and causes a relative "shearing" of the positions of receiving charges. The dominant mode of electromagnetic radiation is dipolar: it has a linear dependence on the positions of the generating charges, and creates a relative translation of the positions of receiving charges.</span></span></span></span>

6 0

3 years ago

Read 2 more answers

Help 10 points!

adell [148]

chemical energy into mechanical energy as well as heat.

3 0

2 years ago

A tennis player tosses a tennis ball straight up and then catches it after 1.25 s at the same height as the point of release.

Alenkasestr [34]

Answer:

A. 9.8 m/s²

B. Zero

C. 6.125 m/s

D. 1.91 m

Explanation:

From the question given above, the following data were obtained:

Time (T) spent in the air = 1.25 s

A. Determination of the acceleration of the ball.

From the description given in question above, the motion of the tennis ball is motion under gravity. Hence, the ball will experience an acceleration due to gravity of 9.8 m/s²

B. Determination of the velocity at maximum height.

Maximum height is the greatest point reached by the tennis ball above the ground. At maximum height, the velocity of the tennis ball is zero since it has no further force to propel it upward.

C. Determination of the initial velocity of the ball.

We'll begin by calculating the time taken to reach the maximum height. This can be obtained as follow:

Time (T) spent in the air = 1.25 s

Time (t) to reach the maximum height =?

T = 2t

1.25 = 2t

Divide both side by 2

t = 1.25 / 2

t = 0.625 s

Finally, we shall determine the initial velocity of the ball. This can be obtained as follow:

Time (t) to reach the maximum height = 0.625 s

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) = 0 (at maximum height)

Initial velocity (u) =?

v = u – gt (since the ball is going against gravity)

0 = u – (9.8 × 0.625)

0 = u – 6.125

Collect like terms

0 + 6.125 = u

u = 6.125 m/s

Thus, the initial velocity of the ball is 6.125 m/s

D. Determination of the maximum height.

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) = 0 (at maximum height)

Initial velocity (u) = 6.125 m/s

Maximum height (h) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = 6.125² – (2 × 9.8 × h)

0 = 37.52 – 19.6h

Collect like terms

0 – 37.52 = – 19.6h

– 37.52 = – 19.6h

Divide both side by – 19.6

h = – 37.52 / – 19.6

h = 1.91 m

Thus, the maximum height reached by the ball is 1.91 m

3 0

3 years ago