The correct answer to the question is : 4000 N
EXPLANATION:
As per the question, the mass of the roller coaster is given as m = 2000 kg
The acceleration of the roller coaster is given as a = 2m/s2
We are asked to calculate the net force acting on the roller coaster.
From Newton's second laws of motion,we know that net external force acting on a particle is equal to the product of mass with acceleration of the particle.
Mathematically it is written as-
F = ma
Hence,net force acting on the roller coaster is calculated as-
F = 2000Kg×2m/s2
= 4000 N.
Here, Newton (N) is the unit of force.
Hence,net force acting on the roller coaster is 4000 N.
Explanation:
The rod is uniform, so the center of gravity is at the center, or 0.75 m from the end. The wedge is 0.5 m from the end, so the center is 0.25 m from the wedge.
Sum the torques about the wedge (it may help to draw a diagram first). Take counterclockwise to be positive.
∑τ = Iα
W (0.25 m) − (100 N) (0.50 m) = 0
W = 200 N
Sum the forces in the y direction.
∑F = ma
F − 100 N − 200 N = 0
F = 300 N
Answer:
soory but i cant under stand it proper can explain
Answer:
-0.4454 Joules
Explanation:
m = Mass of block = 2 kg
h = Height of extension = 17 cm = x
g = Acceleration due to gravity = 9.81 m/s²
Potential energy of the spring
The kinetic energy of the spring
In this system as the potential and kinetic energy is conserved from work energy equivalence we get
The work done by friction is -0.4454 Joules
