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2 years ago

8

Ten-story building has identical stairs throughout its stairways. A student calculates the amount of work required to climb one

set of stairs and the amount of work to climb the entire ten sets.
Which quantity will remain constant in this experiment?

1 answer:

BabaBlast [244]2 years ago

8 0

Answer:

c

Explanation:

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An aircraft performs a maneuver called an "aileron roll." During this maneuver, the plane turns like a screw as it maintains a s

Dmitriy789 [7]

Answer:

0.17724 m/s²

Explanation:

D = Diameter of roll = Length of wing = 11 m

T = Time it takes to complete the circle = 35 s

Velocity

$v=\frac{2\pi R}{T}\\\Rightarrow v=\frac{\pi D}{T}\\\Rightarrow v=\frac{\pi\times 11}{35}\\\Rightarrow v=0.98735\ m/s$

Acceleration

$a=\frac{v^2}{R}\\\Rightarrow a=\frac{0.98735^2}{\frac{11}{2}}\\\Rightarrow a=0.17724\ m/s^2$

Acceleration of the tip of the plane is 0.17724 m/s²

3 0

3 years ago

Acceleration is defined as the rate of change for which characteristic?

Alenkasestr [34]

1) C. velocity

Acceleration is defined as the rate of change of velocity per unit time. In formulas:

$a=\frac{\Delta v}{\Delta t}$

where

$\Delta v$ is the change in velocity

$\Delta t$ is the time interval

Therefore, the correct answer is C. velocity.

2) A. 9.8m/s/s

Earth's gravity is a force, so it produces an acceleration on every object with mass located on the Earth's surface. This acceleration can be calculated, as it is given by the formula

$g=\frac{GM}{r^2}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}$ is the gravitational constant

$M=5.98\cdot 10^{24} kg$ is the Earth's mass

$r=6.37\cdot 10^6 m$ is the Earth's radius

By substituting these numbers into the formula, one can find that the acceleration due to Earth's gravity is $g=9.81 m/s^2$ .

7 0

3 years ago

Read 2 more answers

A sphere of mass 40kg is attaracted by a second sphere of mass 15 kg when their centers are 20 cm apart with a force of 0.1mg-wt

ser-zykov [4K]

<span>gravitational force = 0.1 mg-wt. = 0.1 * 10^-6 * 9.8 N = Gm1m2/r^2
m1 = 40 kg m2 =15 kg and r = 0.2 m
Put in and find G</span>

3 0

3 years ago

Which element would have properties most like helium (He)?

navik [9.2K]

I believe the answer is d

6 0

3 years ago

A 1.0 kg block is attached to an unstretched

KonstantinChe [14]

Answer:

Change in potential energy of the block-spring-Earth

system between Figure 1 and Figure 2 = 1 Nm.

Explanation:

Here, spring constant, k = 50 N/m.

given block comes down eventually 0.2 m below.

here, g = 10 m/s.

let block be at a height h above the ground in figure 1.

⇒In figure 2, potential energy of the block-spring-Earth

system = m×g×(h - 0.2) + 1/2× k × x². where, x = change in spring length.

⇒ Change in potential energy of the block-spring-Earth

system between Figure 1 and Figure 2 = (m×g×(h - 0.2)) - (1/2× k × x²)

= (1×10×0.2) - (1/2×50×0.2×0.2) = 1 Nm.

4 0

3 years ago