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Ghella [55]
3 years ago
14

What is the molarity of a solution in which 0.45 grams of sodium nitrate (NaNO3) are dissolved in 265mL of the solution?

Chemistry
1 answer:
xxTIMURxx [149]3 years ago
6 0

Answer:

M=0.02

Explanation:

85 g NaNO3  -> 1 mol NaNO3

0.45 g NaNO3 ->x

x=(0.45 g NaNO3 * 1 mol NaNO3)/85 g NaNO3       x= 5.3 x 10^-3 mol

265 mL= 0.265 L

M= mol solute/ L solution

M= 5.3 x 10^-3 mol NaNO3/0.265 L            M=0.02

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