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Elis [28]
3 years ago
11

I NEED HELP RIGHT NOW

Chemistry
1 answer:
PolarNik [594]3 years ago
7 0
There are a total of 4 elements
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How is salt water classified?
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Salt water is considered a compound since water is H20 (conpound) and Salt with is NaCl.
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4 years ago
Please solve this question
adell [148]

Answer:

11.c) CO carbon two oxide which burns in limited supply of oxygen

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About one-third of the toxic metal, mercury (Hg), is released into the air from natural sources, such as rocks, soil, volcanoes,
Stolb23 [73]

Answer:

Two-third of the toxic metal, mercury comes from gold mining.

Explanation:

During gold mining small pieces of gold which are within  the soil are separated with the help of mercury. Both gold and mercury are mixed and they forms amalgam. Further gold can be extracted by vaporizing the mercury, thus releasing it into air and contributing to two-third of the air pollution by human activities.

Therefore (d) gold mining is the correct answer.

7 0
3 years ago
A Gas OCCUPIES 525ML AT A PRESSURE OF 85.0 kPa WHAT WOULD THE VOLUME OF THE GAS BE AT THE PRESSURE OF 65.0 kPa
german

Boyle's law of ideal gas: This law states that the volume of a gas is inversely proportional to its pressure at a constant temperature. Acc to this law we can write the relation of pressure and volume as:

PV=Constant

That means:

P_{1}V_{1}=P_{2}V_{2}

From that equation we can calculate Volume of gas at a certain pressure:

P₁=Initial pressure

V₁=Initial volume

P₂=Final pressure

V₂= Final volume

Here P₁, initial pressure is given as 85.0 kPa

V₁, initial volume is given as 525 mL

P₂, final pressure is 65.0 kPa

P_{1}V_{1}=P_{2}V_{2}

so,

V_{2}=85\times 525\div 65

=686 mL

Volume of gas will be 686 mL.

8 0
3 years ago
Read 2 more answers
What is the relative atomic mass of a hypothetical element that consists of the following isotopes in the indicated natural abun
Flauer [41]

Answer:

82.1

Explanation:

Isotopes of the same element are atoms of the same element (so, having same number of protons) having a different number of neutrons (and so, a different atomic mass).

In this problem, this element has 3 different isotopes, with atomic mass (in atomic mass units, a.m.u.) and relative abundance listed below:

1) 78.9 12.6%

2) 80.9 13.9%

3) 82.9 73.5%

In order to calculate the relative atomic mass unit of this element, we have to calculate the weighed average of the relative atomic mass of each isotope.

This means that we can calculate it as the sum of each atomic mass unit multiplied by the relative frequency:

\sum A_i f_i

where A_i is the atomic mass of each isotope and f_i the relative frequency. Therefore, we find:

A=(78.9)(\frac{12.6}{100})+(80.9)(\frac{13.9}{100})+(82.9)(\frac{73.5}{100})=82.1

4 0
3 years ago
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