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olganol [36]
3 years ago
9

Translate the skeleton chemical equation:

Chemistry
1 answer:
Minchanka [31]3 years ago
6 0

Answer:

MgBr₂ + AgNO₃ => Mg(NO₃)₂ + AgBr

Explanation:

Find the element symbol and charge of each element on the periodic table. For polyatomic ions (nitrate), reference your polyatomic ions chart. Use the "partner's charge" rule to find the number of atoms in each compound.

Charges are written as superscripts. "1" is usually not written, just the + or - sign. The charge of silver is 1, which is the (I) bracket roman numeral 1. It is indicated like that because it is multivalent, meaning it has more than one possible charge.

<u>Write each element as an ion</u> (with the charge).

Magnesium is Mg²⁺

Bromide is Br⁻

Silver(I) is Ag⁺

Nitrate is (NO₃)⁻

<u>Write each compound.</u>

REACTANTS SIDE

Magnesium bromide

Mg²⁺Br⁻    Cross over the partner's charge. Since Br is charge 1, Mg has 1 atom. Since Mg has charge 2, Br has 2 atoms.

MgBr₂

Silver(I) nitrate

Ag⁺(NO₃)⁻

AgNO₃       Both have 1 atom because each partner's charge was 1. You do not need to write brackets if nitrate only has 1 atom.

PRODUCTS SIDE

Magnesium nitrate

Mg²⁺(NO₃)⁻

Mg(NO₃)₂      Nitrate has 2 atoms because magnesium's charge is 2.

Silver(I) bromide

Ag⁺Br⁻

AgBr       Both have 1 atom.

Write the compounds into an equation. Reactants go on the left side, products go on the right side. Between the reactants and products, write an arrow.

MgBr₂ + AgNO₃ => Mg(NO₃)₂ + AgBr

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List three examples of a carbon reservoir.
romanna [79]

Answer:

Oceans, Fossil fuels, atmosphere

8 0
3 years ago
Explain why the C―Ha bond is much more acidic than the C―Hb bond in pentan-2-one. Select the single best answer. 253 Ha is less
mafiozo [28]

Answer:

Ha is more acidic than Hb because loss of Ha forms a resonance-stabilized conjugate base.

Explanation:

The carbon atom that is next to the carbonyl group in pentan-2-one is known as the alpha carbon atom, this carbon atom bears the Ha, the alpha hydrogen atoms.

Ha is more acidic than Hb because, loss of Ha leads to the formation of a resonance stabilized enolate ion. This resonance stabilization of the ion formed makes loss of Ha an easier process than loss of Hb, hence the answer above.

3 0
3 years ago
50.0 grams of KCl is dissolved in water to make a 4.00 L
xeze [42]

Answer:0.1677M

Explanation:

Molarity=moles/volume

Number of moles =mass/molar mass

Once you get the number of moles, you apply it to the molarity formula.

8 0
3 years ago
What is the molar solubility of agcl in 0. 30 m nacl at 25°C. ksp for agcl is 1. 77 × 10^-10.
Rzqust [24]

Molar solubility of AgCl will be  0.59 ×  10^{-10} M.

The amount of a chemical that can dissolve in one liter of a solution before reaching saturation is known as its molar solubility. This implies that the quantity of a substance it can disintegrate in a solution even before the solution becomes saturated with that particular substance is determined by its molar solubility.

A compound's molar solubility would be the measure of how many moles of such a compound must dissolve to produce one liter of saturated solution. The molar solubility unit will be mol L-1.

Calculation of molar solubility:

Given data:

M = 0.30 M

K_{sp} = 1.77 × 10^{-10}

The reaction can be written as:

AgCl ⇔ Ag^{+} + Cl^{-}

s            s         (s+0.30)

K_{sp}  = [Ag^{+} ]+ [Cl^{-}]

1.77 × 10^{-10} = s (0.30)

s = 1.77 × 10^{-10}  / 0.3

s = 0.59 ×  10^{-10} M

Therefore, molar solubility of AgCl will be  0.59 ×  10^{-10} M.

To know more about molar solubility

brainly.com/question/16243859

#SPJ4

3 0
1 year ago
a gas occupies 600.0 ml at 20.00 degrees C and 70.00kPa what will be the pressure at 40.00 degrees C and 150.0mL?
Zina [86]

Answer:

P₂ = 299.11 KPa

Explanation:

Given data:

Initial volume = 600 mL

Initial pressure = 70.00 KPa

Initial temperature = 20 °C (20 +273 = 293 K)

Final temperature = 40°C (40+273 = 313 K)

Final volume = 150.0 mL

Final pressure = ?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₂ = P₁V₁ T₂/ T₁ V₂  

P₂ =  70 KPa × 600 mL × 313 K / 293K ×150 mL  

P₂ = 13146000 KPa .mL. K /43950 K.mL

P₂ = 299.11 KPa

4 0
3 years ago
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