Question

The ionization energy of silver is 731 kJ/mol. Is light with a wavelength of 415 nm sufficient to remove an electron from a silver atom in the gaseous phase?

Answer 1

The energy of the light with a wavelength of 415 nm is not sufficient to remove an electron from a silver atom in the gaseous phase.

Energy and wavelength of light

The energy and wavelength of light are related by the formula given below:

• Energy = hc/λ
• where, E = energy
• h = Planck's constant
• c = velocity of light
• λ = wavelength of light

Calculating the energy of the light

From the data provided:

• h = 6.63 × 10^-34 Js
• c = 3.0 × 10^8 m/s
• λ = 415 nm = 4.15 × 10^-7 m

E = (6.63 × 10^-34 × 3.0 × 10^8 m/s)/4.15 × 10^-7 m

E = 4.79 × 10^-19 J

Energy of light is 4.79 × 10^-19 J

Compared with the ionization energy of silver, the energy of the light is far less.

Therefore, the energy of the light with a wavelength of 415 nm is not sufficient to remove an electron from a silver atom in the gaseous phase.

Learn more about about ionization energy and energy of light at: brainly.com/question/14596067