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svetoff [14.1K]
2 years ago
14

Solve for q 7/3 = q + 2/3

Mathematics
2 answers:
antoniya [11.8K]2 years ago
8 0

Answer:

i think its

q = 5/3

kompoz [17]2 years ago
5 0

Answer: q=5/3

Step-by-step explanation:

Let's take our equation

7/3=q+2/3

-2/3   -2/3

5/3=q

q=5/3

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Factorize this term: (a+b)raise to the power of 4 +4
zimovet [89]

Answer:

<u>(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)</u>

Step-by-step explanation:

Given :

  • (a + b)⁴⁺⁴

Solving :

  • (a + b)⁸
  • <u>(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)</u>
8 0
2 years ago
The minimum wage in 2007 was $7.50. The current minimum wage is $13.00. What is the percent of
Nana76 [90]
2007 $7.50. 100%
2021. $13.00. X%
X=100•13/7.5
X=173.33 %
173.33-100%=73.33%
Rounded to nearest tenth 73.3%
3 0
3 years ago
How many positive integer factors of 100! are multiples of 2 or 3?
elena-s [515]

Positive integer factors of 100:

1, 2, 4, 5, 10, 20, 25, 50, 100

Now find if they are a multiple of 2 or 3.

2, 4, 10, 20, 50, 100

That is 6 factors.

3 0
3 years ago
Let X1 and X2 be two random variables following Binomial distribution Bin(n1,p) and Bin(n2,p), respectively. Assume that X1 and
ryzh [129]

Answer:

a) X1+X2 have distribution Bi(n1+n2, p)

b)

P(X1+X2 = 1 | X2 = 0) =  np(1-p)ⁿ¹⁻¹

P(X1+X2 = 1| X2 = 1) = (1-p)ⁿ¹

P(X1 + X2 = 1) = (1-p)ⁿ¹ * np(1-p)ⁿ²⁻¹+ (1-p)ⁿ²*np(1-p)ⁿ¹-¹

Step-by-step explanation:

Since both variables are independent but they have the same probability parameter, you can interpret that like if the experiment that models each try in both variables is the same. When you sum both random variables toguether, what you obtain as a result is the total amount of success in n1+n2 tries of the same experiment, thus X1+X2 have distribution Bi(n1+n2, p).

b)

Note that, if X2 = k, then X1+X2 = 1 is equivalent to X1 = 1-k. Since X1 and X2 are independent, then P(X1+X2 = 1| X2 = K) = P(X1=1-k|X2=k) = P(X1 = 1-k).

If k = 0, then this probability is equal to P(X1 = 1) = np(1-p)ⁿ¹⁻¹

If k = 1, then it is equal to P(X1 = 0) = (1-p)ⁿ¹

Thus,

P(X1+X2 = 1) = P(X1+X2 = 1| X2 = 1) * P(X2=1) + P(X1+X2 = 1| X2 = 0) * P(X2 = 0) = (1-p)ⁿ¹ * np(1-p)ⁿ²⁻¹+ (1-p)ⁿ²*np(1-p)ⁿ¹-¹

4 0
3 years ago
1 1/2 product is sold for every 1/60 of an hour at what unit rate are the products sold?
salantis [7]
I believe the answer is 1 1/2 / minute
3 0
3 years ago
Read 2 more answers
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