The coefficient of the squared expression is 1/9
<h3>How to determine the coefficient of the squared expression?</h3>
A parabola is represented as:
y = a(x - h)^2 + k
Where:
Vertex = (h,k)
From the question, we have:
(h,k) = (-2,-3)
(x,y) = (-5,-2)
So, the equation becomes
-2 = a(-5 + 2)^2 - 3
Add 3 to both sides
1 = a(-5 + 2)^2
Evaluate the sum
1 = a(-3)^2
This gives
1 = 9a
Divide both sides by 9
a = 1/9
Hence, the coefficient of the squared expression is 1/9
Read more about parabolas at:
brainly.com/question/4061870
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Answer:
x ≈ 8.3 ( to the nearest tenth )
Step-by-step explanation:
Using the cosine ratio in the right triangle
cos41° =
=
= 
Multiply both sides by 11
11 × cos41° = x, thus
x ≈ 8.3
Answer:
f(x)=x3−x2−6x2+16x−10
Step-by-step explanation:
If 3−i is a zero, then 3+i
must be a zero as they are conjugates:
f( x ) = ( x − 1 ) ( x − ( 3 − i )) ( x − ( 3 + i )) f ( x ) = ( x − 1 ) ( x2 − x ( 3 + i ) − x ( 3 − i ) + 9 + 1 ) f ( x )) ( x − 1 ) ( x2 − 6x + 10 ) f ( x ) = x3 − x 2 − 6 x 2 + 16x − 10