All categories

3 years ago

What is the value of the expression below when x 3 and y = 8? 6x + 10y

Mathematics

2 answers:

suter [353]3 years ago

7 0

Answer:

Step-by-step explanation:

So we have the expression:

$6x+10y$

And we want to evaluate it when x is 3 and y is 8.

So, substitute:

$=6(3)+10(8)$

Multiply:

$=18+80$

Add:

$=98$

And we're done!

schepotkina [342]3 years ago

5 0

6(3) + 10(8)

18 + 80

=

98

You might be interested in

This cylinder is cut by the plane shown. the plane is perpendicular to the base of the cylinder. what is the shape of the cross-

densk [106]

I cannot see your picture, but if the plane cutting the cylinder is indeed perpendicular to the cylinder's base, then the cross section must be square or rectangular. Going by the shape of most cylinders, I would guess that it is rectangular.

4 0

3 years ago

Read 2 more answers

What is (3x^3)^3 in factored form? Help

Sergio [31]

Answer:

This can't really be factored, but it can be expanded slightly.

(3x³)³ = 27x⁹

4 0

3 years ago

????????????????????

Shtirlitz [24]

It’s a diagram ur welcome

3 0

3 years ago

Shelly is 3 years older than Michelle. 4 years ago the sum of their ages was 67. find the age of each person now

Murljashka [212]

If Shelly is 3 years older than Michael and There 67. Michael is 64 and Shelly is 67. Or Michael is 67 and Shelly is 70.

Hope I helped. Have a wonderful day

3 0

3 years ago

A cement walkway of uniform width has been built around an in-ground rectangular pool. the area of the walkway is 1344 square fe

Elza [17]

Answer:

6 feet.

Step-by-step explanation:

Dimensions of the Pool =80 feet long by 20 feet wide

Area of the walkway =1344 square feet.

If the width of the walkway=w

Length of the Larger Rectangle =80+2w
Width of the Larger Rectangle =20+2w

Area of the Walkway =Area of the Larger Rectangle - Area of the Pool

$1344=(80+2w)(20+2w)-(80*20)\\1344=80*20+160w+40w+4w^2-80*20\\4w^2+200w=1344\\4w^2+200w-1344=0\\We factorize\\4(w^2+50w-336)=0\\4(w^2-6w+56w-336)=0\\w(w-6)+56(w-6)=0\\(w-6)(w+56)=0\\w-6=0$ or $ w+56=0\\w=6$ ft or $ w=-56$ \\Therefore, the width of the walkway , w=6 feet.$

6 0

3 years ago