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Gwar [14]
3 years ago
8

Find a general linear equation Ax+By+C=0 of the straight line that passes through the point (1,1) and has slope 1/5.

Mathematics
1 answer:
dedylja [7]3 years ago
5 0
\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 1}}\quad ,&{{ 1}})\quad 
%   (c,d)

\end{array}
\\\quad \\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies\cfrac{1}{5}
\\ \quad \\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad 
\begin{array}{llll}
\textit{plug in the values}\\
\textit{and move everything to}\\
\textit{the left-side}
\end{array}\\
\qquad \uparrow\\
\textit{point-slope form}
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Answer:

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A trick I know is if you add all the digits of the number and they add up to a multiple of 3, it is divisible by 3.

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