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aniked [119]
3 years ago
6

What is sin45°*sin30°*cos60°

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
6 0

Answer:

\frac{\sqrt{2} }{8}

Step-by-step explanation:

Using the exact values of the given trig functions, then

sin45° × sin30° × cos60°

= \frac{\sqrt{2} }{2} × \frac{1}{2} × \frac{1}{2} = \frac{\sqrt{2} }{8}

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Which completely describes the polygon?
bogdanovich [222]

option D none of the above

4 0
3 years ago
Answer and explanation plz ???
Nutka1998 [239]

Answer:

25

Step-by-step explanation:

Formula

2xy + 1

Givens

x = 3

y = 4

Solve

2*(3)*(4) + 1

24 + 1

25

7 0
3 years ago
How do I solve this equation? Please, if you will, explain.
Licemer1 [7]
Yes, but your answer will be a decimal, but make sure you check your work and one way you can check your work is by first combing like terms, and then solve it as it is an equation. 

7 0
3 years ago
Read 2 more answers
Reading list
never [62]

9514 1404 393

Answer:

  7 cm, 4.4 cm

Step-by-step explanation:

The side lengths can be found from the law of cosines. Each triangle has legs 3 cm and 5 cm. The angle between these will be 60° or 120°. Then the two sides of the parallelogram are ...

  s = √(a² +b² -2ab·cos(C))

  s = √(3² +5² -2·3·5·(±1/2)) = √(34 ±15) = {√49, √19}

The two side lengths are 7 cm and about 4.4 cm.

8 0
3 years ago
Please help me :)))))
svetoff [14.1K]
Part a)

Answer: 5*sqrt(2pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(50/pi)
r = sqrt(50)/sqrt(pi)
r = (sqrt(50)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(50pi)/pi
r = sqrt(25*2pi)/pi
r = sqrt(25)*sqrt(2pi)/pi
r = 5*sqrt(2pi)/pi

Note: the denominator is technically not able to be rationalized because of the pi there. There is no value we can multiply pi by so that we end up with a rational value. We could try 1/pi, but that will eventually lead back to having pi in the denominator. I think your teacher may have made a typo when s/he wrote "rationalize all denominators"

============================================================

Part b)

Answer: 3*sqrt(3pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(27/pi)
r = sqrt(27)/sqrt(pi)
r = (sqrt(27)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(27pi)/pi
r = sqrt(9*3pi)/pi
r = sqrt(9)*sqrt(3pi)/pi
r = 3*sqrt(3pi)/pi

Note: the same issue comes up as before in part a)

============================================================

Part c)

Answer: sqrt(19pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(19/pi)
r = sqrt(19)/sqrt(pi)
r = (sqrt(19)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(19pi)/pi
8 0
3 years ago
Read 2 more answers
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