Question

Which table shows a proportional relationship between weight and price?

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

second table (see the attached figure)

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

Verify each table

First table

Let

x ----> the weight in lb

y ----> the price in dollars

For x=1.5, y=3.50

Find the value of the constant of proportionality k

$k=y/x$ ----> $k=3.5\1.5=2.33$

For x=2, y=7

$k=y/x$ ----> $k=7/2=3.5$

The values of k are different

therefore

This table not represent a  proportional relationship between weight and price

Second table

Let

x ----> the weight in g

y ----> the price in dollars

For x=1.5, y=0.90

Find the value of the constant of proportionality k

$k=y/x$ ----> $k=0.90\1.5=0.6$

For x=8, y=4.80

$k=y/x$ ----> $k=4.8/8=0.6$

The values of k are equal

therefore

This table represent a  proportional relationship between weight and price

Third table

Let

x ----> the weight in kg

y ----> the price in dollars

For x=2, y=0.75

Find the value of the constant of proportionality k

$k=y/x$ ----> $k=0.75/2=0.375$

For x=5, y=3.75

$k=y/x$ ----> $k=3.75/5=0,75$

The values of k are different

therefore

This table not represent a  proportional relationship between weight and price

Fourth table

Let

x ----> the weight in oz

y ----> the price in dollars

For x=2 oz, y=4

Find the value of the constant of proportionality k

$k=y/x$ ----> $k=4/2=2$

For x=4 lb, y=8

convert to oz

1 lb=16 oz

4 lb=64 oz

$k=y/x$ ----> $k=8/64=0,125$

The values of k are different

therefore

This table not represent a  proportional relationship between weight and price