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Alinara [238K]
2 years ago
7

If f(x) = 27 +3 and g(x) = x - 7, find (f - g)(x).

Mathematics
2 answers:
lara31 [8.8K]2 years ago
7 0

Answer:

<h2>(f - g)(x) = 26x + 10</h2>

Step-by-step explanation:

(f - g)(x) = f(x) - g(x)

We have f(x) = 27x + 3 and g(x) = x - 7. Substitute:

(f - g)(x) = (27x + 3) - (x - 7)

(f - g)(x) = 27x + 3 - x - (-7)

(f - g)(x) = 27x + 3 - x + 7             <em>combine like terms</em>

(f - g)(x) = (27x - x) + (3 + 7)

(f - g)(x) = 26x + 10

KatRina [158]2 years ago
3 0

Answer:

(f - g)(x) = 37 - x

Step-by-step explanation:

(f - g)(x) = (27 +3) - (x - 7)

            = 27 + 3 - x + 7

            = 37 - x

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Calvin had 30 minutes in time-out. For the first 23 1/3 minutes, Calvin counted spots on the ceiling. For the rest of the time,
scoundrel [369]

Answer: \frac{20}{3}\ minutes or 6 \frac{2}{3}\ minutes

Step-by-step explanation:

For this exercise you can convert the mixed number to an improper fraction:

1. Multiply the whole number part by the denominator of the fraction.

2. Add the product obtained and the numerator of the fraction (This will be the new numerator).

3. The denominator does not change.

Then:

23\frac{1}{3}= \frac{(23*3)+1}{3}= \frac{70}{3}\ minutes

You know that he had 30 minutes in time-out, he counted spots on the ceiling for \frac{70}{3} minutes and the rest of the time he made faces at his stuffed tiger.

Then, in order to calculate the time Calvin spent making faces at his stuffed tiger, you need to subract 30 minutes and \frac{70}{3} minutes:

30\ min-\frac{70}{3}=(\frac{3(30)-70}{3})=\frac{20}{3}\ minutes or 6 \frac{2}{3}\ minutes

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3 years ago
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Step-by-step explanation:

5 0
3 years ago
a group of 60 children went on a trip to the zoo 7/10 of the children had never been there how many children went to the zoo for
zvonat [6]

Answer:

42

Step-by-step explanation:

as you divide 10 into 60 and then multiply it by 7 and your answer will be 42

5 0
2 years ago
2. In a school of 320 students, 85 students are in the band, 200 students are on sports teams, and 60 students
Alja [10]

Answer:

<u>60</u> students are involved in either band or sports.

<u>95</u> students  are not involved in either sports or band.

Step-by-step explanation:

Given:

In a school of 320 students, 85 students are in the band, 200 students are on sports teams, and 60 students  participate in both activities.

Now, to find the students  are involved in either sports or band. And students who are not involved in either sports or band.

<em>Total number of students</em> = 320.

Number of students in the band = 85.

Number of students in the sports team = 200.

Number of students participate in both activities = 60.

Thus, 60 students are involved in either band or sports.

So, the number of students in the band adding number of students in the sports team we get:

200 + 85 = 285.

Then, to subtract the number of students participate in both activities we get:

285 - 60 = 225.

<em>Thus, the remaining students are </em>= 225.

Now, to get the students  who are not involved in either sports or band we subtract the total number of students from the remaining students:

320-225

=95.

Therefore, 60 students are not involved in either band or sports. 95 students  are not involved in either sports or band.

8 0
2 years ago
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