Answer:
"g(x) = log₂(x) + 2" is the closest graph to what g(x) would be, slightly above f(x) and curving up.
Answer:
Step-by-step explanation:
Each ticket is $15. The number of tickets is what we are trying to solve for. The class spends a certain amount of money to prepare for the formal. They hope that the money they make in ticket sales is MORE than what they spend. The expression that represents the number of tickets at $15 each is 15x, where x is the number of tickets. They hope that the sales are greater than what they spend, so what we have so far is
15x >
Greater than what, though? What do they spend? They spend 600 for the food, so
15x > 600...
but they also have to print a certain, unknown number of tickets at .50 each. The expression that represents the printing of each ticket is .5x (we can drop the 0; it doesn't change the answer or make it wrong if we drop it off). So the cost for this affair is the food + the printing.
15x > 600 + .5x
Solve this inequality for x. Begin by subtracting .5 from both sides to get
14.5x > 600 so
x > 41.3
Because we are not selling (or printing) .3 of a ticket, it's safe to say (and also correct!) that they need to sell (and print) 41 tickets. If they sell 41 tickets, the profit is found by
15(41) > 600 + .5(41)
615 > 600
This means that at 41 tickets, they make a profit. At 40 tickets, the inequality looks like this:
15(40) > 600 + .5(40) and
600 > 620. This is not true, so 40 tickets isn't enough.
Answer: c
Step-by-step explanation:
The weight of a 170 cm steel bar will be 5 Kg
Step-by-step explanation:
Derek uses a 136 cm flat steel bar that weighs 4 kg to make rack in the garage.
1 kg = 1000 gm
So the weight of 1 cm steel bar will be 
kg
Weight of 1 cm bar = 
gm
Let the weight of a 170 cm steel bar will be 
× 
gm
⇒
× 
gm
⇒ 5000 gm
⇒5 kg
Hence, the weight of a 170 cm steel bar will be 5 Kg
