What’s 80 percent in fractions
2 answers:
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Using the binomial distribution, it is found that there is a 0.5 = 50% probability of selecting a two-child family with one boy and one girl.
For each child, there are only two possible outcomes, either it is a boy, or it is a girl. The probability of a child being a boy or being a girl is independent of any other child, which means that the binomial distribution is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- Two children, hence
.
- Equally as likely to be a boy or a girl, hence
.
The probability of one of each is P(X = 1), hence:
0.5 = 50% probability of selecting a two-child family with one boy and one girl.
A similar problem is given at brainly.com/question/24863377
Answer:
Step-by-step explanation:
Given are the vertices of a quadrilateral.
WE have to find the name of the quadrilateral
WE have slope of AC = (5-1)/(7-3) = 1
and slope of BD = (2-5)/(7-4) = -1
Since m1m2 =-1 we get
the diagonals cut at right angles
This property is special property for square, rhombus and kite only.
Let us check if diagonals bisect each other
Mid point of AC =
Mid point of BD =
Since diagonals do not bisect this is neither rhombus nor square.
Only possibility is kite