<span>ds=<span>√<span>1+<span><span>(<span><span>dy</span><span>dx</span></span>)</span>2</span></span></span><span>dx</span>=<span>√<span>1+<span>14</span><span>(<span>x4</span>−2+<span>1<span>x4</span></span>)</span></span></span><span>dx</span></span>
<span>=<span>√<span><span>14</span><span>(<span>x4</span>+2+<span>1<span>x4</span></span>)</span></span></span><span>dx</span>=<span>√<span><span>1<span>22</span></span><span><span>(<span>x2</span>+<span>1<span>x2</span></span>)</span>2</span></span></span><span>dx</span></span>
<span>=<span>12</span><span>(<span>x2</span>+<span>1<span>x2</span></span>)</span><span>d<span>x</span></span></span>
Old. new
100%. 45%
x. 42
45x= 4200
x=$93.33
Answer:
Step-by-step explanation:
Let c represent the number of children that attended the concert.
Let a represent the number of adults that attended the concert.
At one of the concerts, each adult brought 4 children with them, and 10 children attended without an adult. This means that the number of children that attended is
c = 4a + 10
Tickets for a concert were $5 for each child and $8 for each adult. The total ticket sales were $1730. It means that
5c + 8a = 1730
Therefore, the systems of equations that can be solved to determine the number of children, c, and adults that attended the concert is
c = 4a + 10
5c + 8a = 1730
The correct answer is 15.
