Answer:
the answer would be 56 minutes.
Step-by-step explanation:
7 x 40 = 280
5n = 280
n = 56
So if you're adding two negatives you move left, positive you move right, and when you have to determine a negative, and a positive you just have to see which one is the farthest from zero which the farthest one's sign is either positive, or negative. Positive to move right, and negative to move left.
I’m pretty sure the second questions answer is y=3x+2
Answer:
1. 125
2. 25
3. 40
4. 39
First question:
(15-10)^2 + (15-5)^2
parentheses first to get 5^2 + (15-5)^2
exponents next to get 25 + (15-5)^2
parentheses again 25 + 10^2
exponents again 25 + 100 = 125
Second question:
simplify the exponents (3 *3) + (4 * 4) + (2 * 2) to get 9 + 16 + 4 = 29
Third question:
simplify in the parentheses 6 1/7 - 1/7 = 6
divide 60 by 6 to get 10
multiply 10 by 4 to get 40!
Fourth question:
simplify the fractions to get 1/3 + 8/3 = 3
multiply the 3 by 13 to get 39
Answer:
(a) 9 buildings
(b) 2^n -1
Step-by-step explanation:
The number of distinct non-empty subsets of b objects is 2^b -1. Since the subsets are distinct, each could represent a list of the buildings, from the set of b buildings, in which a student is taking courses.
(a) For 8 buildings, 2^8 -1 = 255 students could enroll. for 9 buildings, 2^9-1 = 511 students could enroll.
For 500 students, 9 buildings are required.
__
(b) The maximum number of students for n buildings is ...
2^n -1
