Very simple.
Let's say you have an equation.
f(x) = x^2
You are asked to find the value for y when x equals 1.
The new equation is: f(1) = (1)^2
f(1) = 1
When x = 1, y = 1.
The same concept is applied here.
In the graph, where does x equal 0?
It equals zero at the origin.
Is there any y-value associated with 0?
Yes, there is.
Y equals five when x equals 0.
So
h(0) = 5
Answer:
Step-by-step explanation:
Answer:
4 = 2*1+1
Step-by-step explanation:
Answer:
you have you have and equation and then plug 7,8 into t and you get your awnser
Step-by-step explanation:
get your equationn by Reding the graph or table then to y2 minus y1 over x2 minus x1 and then look at the graph for the y-int and but then , in to t