Answer:
a) (momentum of the elephant), p1 = 14625 kg×m/s
b) p1 = 609.4×p2
c) (momentum of the hunter), p3 = 720 kg×m/s.
Explanation:
a) if m = 1950 kg is the mass of the elephant and V = 7.50 m/s be the speed of the elephant, then the momentum is given by:
p1 = m×V = (1950)×(7.50) = 14625 kg×m/s
b) if m = 0.0400 kg is the mass of the bullet and v = 600 m/s be the speed of the bullet, then the momentum of the bullet is given by:
p2 = m×v = (0.0400)×(600) = 24 kg.m/s
then:
p1/p2 = (14625)/(24) = 609.4
that is, p1 = 609.4×p2
Therefore, the momentum of the elephant is 609.4 times the momentum of the bullet.
c) the momentum og the hunter after missing the elephant is given by:
p3 = m×v = (90.0)×(8) = 720 kg.m/s
Therefore, the momentum of the hunter is 720 kg×m/s.
