#3). Your drawing in the lower right corner is correct. You're headed down the right road, but ran out of gas and just stopped.
Radius of the circle = 1.5 km
Circumference of the whole circle = (2·π·radius) = 9.42 km
Distance = 3/4 of the way around it = 7.07 km .
Displacement = the straight line from the West point to the North point. The straight-line length is 2.12 km; the straight-line direction from start to finish is Northeast (45°). I'll let you figure out why these numbers.
#4). What if you walk 1 mile East and then 1 mile West ? You got a good workout, and you're back home where you started ! Your distance is 2 miles, and your displacement is zero.
The whale had a good workout too. She swam (6.9 + 1.8 + 3.7) = 12.4 km. She's sweating and tired. Her total distance during that workout is 12.4 km.
Her displacement is the line from start-point to end-point. How she got there doesn't matter, so swimming 1 km East and then swimming 1 km West cancel out, and have no effect on the displacement.
(6.9E + 1.8W + 3.7E) = (10.6 E) + (1.8 W) . . . That adds up to 8.8 East ! That's where she ends up. That's her displacement ... 8.8 km East of where she started. Since we're only talking about displacement, we don't care HOW she got there. She might have been swimming big 20-km circles all day. We don't know. All we know is that she ended up 8.8 km East of where she started.
Waxing gibbous
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Answer:
No, you can't keep on dividing the charge forever.
Explanation:
No, you can't keep on dividing the charge in that manner forever because the total charge of the stick is an integer multiples of individual units known as an elementary charge, <em>which is the electron (e) charge (e = 1.602x10⁻¹⁹C)</em>.
Therefore the limit of the division of the original charge will be the electron charge since it is the smallest charge that can exist freely.
I hope it helps you!
Okayyyyyyyyyy....................
<span>Remember that impulse = change in
momentum
this means we compute the momentum of the ball just before impression and just
after; we know the mass, so we find the speeds
the ball falls for 1.5m and will achieve a speed given by energy
conservation:
1/2 mv^2 = mgh => v=sqrt[2gh]=5.42m/s
since it rises only to 0.85 m, we compute the initial speed after power from
the same equation and get
v(after)=sqrt[2*9.81m/s/s*0.85m] = 4.0837 m...
now, recall that momentum is a vector, so that the momentum down has one sign and
the momentum up has a positive sign, so we have
impulse = delta (mv) = m delta v = 0.014 kx (4.08m/s - (-5.42m/s) = 0.133 kgm/s </span>
