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Sophie [7]
3 years ago
7

Calculate the percent of acetic acid in the vinegar. (The density of vinegar is 1.002 g/ml.)

Chemistry
1 answer:
Orlov [11]3 years ago
5 0
You have to optiosn to solve this. Let me explain both of them: The percent acidity, i.e. the percent acetic acid in a sample of vinegar is calculated by the following equation:

% acidity = (grams of acetic acid / grams of vinegar) x 100

The other method you can use is to remember that in order to calculate the percent acetic acid in the vinegar solution by mass you can assume the density of the vinegar solution is the same as water (1.00 g/ml).  The formula will be:

grams of vinegar solution = density of vinegar solution x volume of vinegar solution

For example if 5 ml of the vinegar solution was used and if we assume that  density of the vinegar solution is 1.00 g/ml then 

grams of vinegar solution =  1.00 g / ml x 5 ml  = 5 grams

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3 years ago
Determine the concentration of a solution (M) made by dissolving 18.8 g of sodium chloride (NaCl) in 750.0 mL of solution.
Viefleur [7K]

Answer:

0.429 M

Explanation:

To find the molarity, you need to (1) convert grams to moles (using the molar mass), then (2) convert mL to L, and then (3) calculate the molarity (using the molarity ratio).

(Step 1)

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

18.8 grams NaCl               1 mole
--------------------------  x  ------------------------  =  0.322 moles NaCl
                                     58.443 grams

(Step 2)

1,000 mL = L

 750.0 mL                1 L
------------------  x  -----------------  =  0.7500 L
                            1,000 mL

(Step 3)

Molarity (M) = moles / volume (L)

Molarity = 0.332 moles / 0.7500 L

Molarity = 0.429 M

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2 years ago
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