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labwork [276]
3 years ago
10

How many protons, neutrons, and electrons would be found in flourine - 20?

Chemistry
1 answer:
RoseWind [281]3 years ago
5 0

In the most common isotope of fluorine, fluorine-19, it has 19 electrons, 9 protons and 10 neutrons. Hope this helps you! Good luck!!

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Important of thermometer​
Mama L [17]

Answer:

to see if something or someone has either a low or high temperature

Explanation:

because you wanna know if some has a fever so you dont get the coronna virus

7 0
3 years ago
Question 3
Anni [7]

Answer:

True

Explanation:

Sometimes you will need to convert from grams to moles, or moles to grams

5 0
3 years ago
Explain the advantage of using scientific names,
posledela

Answer:

Clarity and precision - these names are unique with each creature having only one scientific name. Helps avoid confusion created by common names. 3. Universal recognition - scientific names are standardised and accepted universally

Explanation:

4 0
3 years ago
how do i caculate the trmperature change that 725 grams of aluminum will undergo when 2.35x10^4 Joules of thermal energy are add
sesenic [268]

Answer:

36°C

Explanation:

Given parameters:

Mass of aluminum = 725g

Quantity of heat  = 2.35 x 10⁴J

Unknown:

Temperature change  = ?

Solution:

To solve this problem, we simply use the expression below:

  The quantity of energy is given as:

          Q  = m C Δt

Q is the quantity of energy

m is the mass

C is the specific heat capacity of aluminum  = 0.9J/g°C

Δt is the change in temperature

  The unknown is Δt;

             Δt  = \frac{Q}{mc}    = \frac{2.35 x 10^{4} }{725 x 0.9}    = 36°C

4 0
3 years ago
An analytical chemist is titrating of a solution of hydrazoic acid with a solution of . The of hydrazoic acid is . Calculate the
serg [7]

Answer:

pH = 12.43

Explanation:

<em>...is titrating 212.7 mL of a 0.6800 M solution of hydrazoic acid (HN3) with a 0.2900 M solution of KOH. The p Ka of hydrazoic acid is 4.72. Calculate the pH of the acid solution after the chemist has added 571.6 mL of the KOH solution to it</em>.

To solve this question we need to know that hidrazoic acid reacts with KOH as follows:

HN3 + KOH → KN3 + H2O

<em>Moles KOH:</em>

0.5716L * (0.2900mol /L) =0.1658 moles of KOH

<em>Moles HN3:</em>

0.2127L * (0.6800mol/L) = 0.1446 moles HN3

As the reaction is 1:1, the KOH is in excess. The moles in excess of KOH are:

0.1658 moles - 0.1446 moles =

0.0212 mol KOH

In 212.7mL + 571.6mL = 784.3mL = 0.7843L

The molarity of KOH = [OH-] is:

0.0212 mol KOH / 0.7843L = 0.027M = [OH-]

The pOH is defined as -log [OH-]

pOH = -log 0.027M

pOH = 1.57

pH = 14 - pOH

pH = 12.43

6 0
3 years ago
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