Answer:
Step-by-step explanation:
<span>2a(cubed) - 2a(squared) - 7a + 7
</span><span>= 2a^3 - 2a^2 - 7a + 7
= 2a^2 (a -1) - 7 (a -1)
= (a - 1)(2a^2 - 7)
(a - 1) and </span>(2a^2 - 7) are factors
answer
<span>A) (a - 1) </span>
<span>the sum of three consecutive odd integers is 69. Find the integers.
-------------
1st: 2x-1
2nd: 2x+1
3rd: 2x+3
---------------------
Equation:</span>2x-1 + 2x+1 + 2x+3 = 69<span>
</span><span>6x + 3 = 69
2x + 1 = 23
-----------------
So 2x-1 = 21
And 2x+3 = 25
</span><span>let:
x be the first odd integer
x + 2 be the 2nd odd integer
x + 4 be the 3rd odd integer
solution:
1st odd integer + 2nd odd integer + 3rd odd integer = 69
x + (x+2) + (x+4)= 69
</span>
<span>3x + 6 = 69
3x = 69 - 6
3x = 63 (dividing both sides by three)
x = 21
_______________________________________
x=21
x+2=23
x+4=25
therefore, the 1st integer is 21, the 2nd is 23 and the 3rd is 25..</span>
Answer:
b I did the test already
Step-by-step explanation:
B
