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Damm [24]
3 years ago
6

Simplify. (-8V2)(+1/2V32)

Mathematics
1 answer:
erastovalidia [21]3 years ago
6 0

Hello!!

\rule{300}{5}

\huge\blue{{\fbox{\tt{ANSWER:-\:}}}}

-32

\huge\red{{\underline{\overline{\textbf{MY\:EXPLANATION~!}}}}}

Apply rule:  (-a) = -a

(-8\sqrt{2}) = - 8\sqrt{2}

= -8\sqrt{2}~\frac{1}{2}\sqrt{32}

\sqrt{2}~\sqrt{32} =\sqrt{64}

= -8\sqrt{64}~\frac{1}2}

\sqrt{64} = 8

= -8 · 8 · \frac{1}{2}

Multiply the numbers: -~8 · 8= -64

=-64 · \frac{1}{2} = -32

= -32

Hope It Helps. . .

#LearnWithBrainly

\huge\blue{{\fbox{\tt{ANSWER:-\:}}}}

\bold{Jace\;} ^-^

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Answer:

There is sufficient statistical evidence to suggest that the US presidents are taller than the average American male

Step-by-step explanation:

The given parameters are;

The mean height of American Males, μ = 69.5 inches

The mean height of 43 male presidents, \overline x = 70.78

The standard deviation, s = 2.77 inches

The number of male presidents = 43

The null hypothesis; H₀ μ = \overline x

The alternative hypothesis; Hₐ μ ≠ \overline x

The significance level, α = 0.05

The t test for the sample with unknown population standard deviation is given as follows;

t=\dfrac{\bar{x}-\mu }{\dfrac{s }{\sqrt{n}}}

Therefore, we have;

t=\dfrac{70.78-69.5 }{\dfrac{2.77 }{\sqrt{43}}} \approx 3.0302

The degrees of freedom, df = n - 1 = 43 - 1 = 42

The critical 't' value = 2.0181

Therefore, given that the t test value is larger than the critical-t, we reject the null hypothesis, therefore, there is sufficient statistical evidence to suggest that the US presidents are taller than the average American male

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