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weqwewe [10]
3 years ago
11

From prophase through metaphase of mitosis, each chromosome has _____ DNA molecule(s), while from anaphase through telophase of

mitosis, each chromosome has _____ DNA molecule(s)
Biology
1 answer:
steposvetlana [31]3 years ago
5 0

From prophase through metaphase of mitosis, each chromosome has 2 DNA molecule(s), while from anaphase through telophase of mitosis, each chromosome has one DNA molecule.

Explanation:

Mitosis is a process in which 2 identical daughter cells are formed in which DNA gets split into two sets of chromosome.

Mitosis occurs in four phases: Prophase, metaphase, Anaphase and Telophase.

After the G2 phase the DNA amount increases and get ready for the division here sister chromatid are seen not chromosome.

In metaphase the chromosome align at the equatorial plate and readied to separate the sister chromatids easily. Each chromatid contains 1 DNA molecule, in this phase two sister chromatids are there so 2 molecules of DNA are present.

In Anaphase the sister chromatids are pulled towards the opposite ends. Each cell receives one chromatid which is now 2 chromosmes. So one chromatid will have one DNA molecule.

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This shows us that two moles of potassium nitrate are formed from 1 mole of lead nitrate or potassium chromate solution. The next step is to find out how many moles of each reactant there are. Note the word Molar is a concentration that simply means moles per liter.

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The important part here is to see that the number of moles of the reactants are different. We know the number of moles of products will be dependent on the number of moles of reactants, and in this case there is less potassium chromate than there is lead nitrate, so this is the limiting factor as there is a one to one relationship with both reactants. Therefore, the number of moles of potassium nitrate produced is 2 x number of moles of potassium chromate. i.e. 6.325 moles of potassium nitrate is liberated.

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Now we simply times the molar mass by the number of moles to yield the final grams liberated: 6.325 moles  x 101.1 grams/mole = 639.4 grams of potassium nitrate is liberated from this reaction.
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