What is the approximate volume of a cone with a height of 12 in. and radius of 9 in.?

Carlos earns $11 per hour at his job. Let x represent the number of hours he worked in May. Let y represent the number of hours

Firlakuza [10]

11x+11y

11(x+y)

Explanation

Step 1

Let

Carlos earns == 11 per hour

x represents the number of hours he worked in May

the,

the amount he earned in Mayis

$11\cdot x=11x$

y represent the number of hours he worked in June.

the amount he earned in June was

$11\cdot y=11y$

Step 2

the amount of money he earned is May and June is the sum of the values

$\begin{gathered} \text{total}= \\ 11x+11y \\ \text{if we factorize 11} \\ 11(x+y) \end{gathered}$

I hope this helps you

5 0

10 months ago

33. Suppose you were on a planet where the

tatyana61 [14]

Answer:

a) 3.675 m

b) 3.67m

Explanation:

We are given acceleration due to gravity on earth = $9.8ms^-2$

And on planet given = $2.0ms^-2$

A) Since the maximum jump height is given by the formula

$\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}$

Where H = max jump height,

v0 = velocity of jump,

Ø = angle of jump and

g = acceleration due to gravity

Considering velocity and angle in both cases

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}$

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)

g1 = 2.0 $ms^-2$ and

g2 = 9.8 $ms^-2$

Substituting these values we get H1 = 3.675m which is the required answer

B) Formula to find height of ball thrown is given by

$\mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}$

which is due to projectile motion of ball

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}$

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0 $ms^-2$ and g2 = 9.8 $ms^-2$

We get h1 = 3.67m which is the required height

6 0

3 years ago

-4(9n + 9) = -12(4n - 6).

WITCHER [35]

Answer:

n = 9

Step-by-step explanation:

Step 1: Write equation

-4(9n + 9) = -12(4n - 6)

Step 2: Solve for n

Distribute: -36n - 36 = -48n + 72

Add 48n to both sides: 12n - 36 = 72

Add 36 to both sides: 12n = 108

Divide both sides by 12: n = 9

Step 3: Check

Plug in n to verify if it's a solution.

-4(9(9) + 9) = -12(4(9) - 6)

-4(81 + 9) = -12(36 - 6)

-4(90) = -12(30)

-360 = -360

7 0

3 years ago

U.S. city with a ZIP code containing the first 5 digits of pi, beginning with the 3

dlinn [17]

31415 = Savannah, Georgia

8 0

3 years ago

Read 2 more answers

Given f(x)=-1/7√16-x^2 find f^-1(x)

Vera_Pavlovna [14]

Answer:

$f^{-1}(x)=\pm \sqrt{49x^2-16}$

Not a function.

Step-by-step explanation:

The given function is;

$f(x)=-\frac{1}{7}\sqrt{16-x^2}$

Let $y=-\frac{1}{7}\sqrt{16-x^2}$

Interchange x and y;

$x=-\frac{1}{7}\sqrt{16-y^2}$

Solve for y;

$-7x=\sqrt{16-y^2}$

Square both sides

$(-7x)^2=(\sqrt{16-y^2})^2$

$49x^2^2=16-y^2$

$49x^2^2-16=y^2$

$y=\pm \sqrt{49x^2-16}$

The inverse is

$f^{-1}(x)=\pm \sqrt{49x^2-16}$

$f^{-1}(x)=\pm \sqrt{49x^2-16}$ is not a function because one x-value maps onto to different y-values.

6 0

3 years ago