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bekas [8.4K]
3 years ago
5

BEST ANSWER GETS BRAINLIEST! What expression represents the area of the triangle? A triangle has a base of 24 and a height of 10

. Another side has a length of 26.
One-half times 10 times 24
One-half times 10 times 26
One-half times 24 times 26
One-half times 10 times 24 times 26
Mathematics
2 answers:
Alborosie3 years ago
7 0

Answer:

One-half times 10 times 24

Step-by-step explanation:

area \: of \: triangle  =  \frac{1}{2}  \times height \times base \\  \\ area \: of \: triangle  =  \frac{1}{2}  \times   10 \times 24

lana [24]3 years ago
5 0

Answer:

One-half times 10 times 24

Step-by-step explanation:

A= 1/2bh

A= 1/2*24*10=120

One-half times 10 times 24

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A right isosceles triangle has an area of 65cm^2. What's the length of each leg to the nearest tenth of a cm.
Andreas93 [3]

Well, we know that the legs of this triangle are equal, and we know
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Since this is a right triangle, we can set it down on one leg, and then
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    Area = (1/2) (base) (height)

             = (1/2) (leg) (leg)

    65 cm²  =  (1/2) (leg)²

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Take the square root of each side:      leg = √130 cm²  =  11.402 cm

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At 3:30 p.m., you have 15 megabytes of a movie. At 3:45 p.m., you have 75 megabytes. What is the download rate in megabytes per
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7 0
3 years ago
2logx=3-2log(x+3) solve for x​
AVprozaik [17]

Answer:

\large\boxed{x=\dfrac{-3+\sqrt{40+10\sqrt{10}}}{2}}

Step-by-step explanation:

2\log x=3-2\log(x+3)\\\\Domain:\ x>0\ \wedge\ x+3>0\to x>-3\\\\D:x>0\\============================\\2\log x=3-2\log(x+3)\qquad\text{add}\ 2\log(x+3)\ \text{to both sides}\\\\2\log x+2\log(x+3)=3\qquad\text{divide both sides by 2}\\\\\log x+\log(x+3)=\dfrac{3}{2}\qquad\text{use}\ \log_ab+\log_ac=\log_a(bc)\\\\\log\bigg(x(x+3)\bigg)=\dfrac{3}{2}\qquad\text{use the de}\text{finition of a logarithm}\\\\x(x+3)=10^\frac{3}{2}\qquad\text{use the distributive property}

x^2+3x=10^{1\frac{1}{2}}\\\\x^2+3x=10^{1+\frac{1}{2}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\x^2+3x=10\cdot10^\frac{1}{2}\qquad\text{use}\ \sqrt[n]{a}=a^\frac{1}{n}\\\\x^2+3x=10\sqrt{10}\qquad\text{subtract}\ 10\sqrt{10}\ \text{from both sides}\\\\x^2+3x-10\sqrt{10}=0\\\\\text{Use the quadratic formula}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\a=1,\ b=3,\ c=-10\sqrt{10}\\\\b^2-4ac=3^2-4(1)(-10\sqrt{10})=9+40\sqrt{10}\\\\x=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2(1)}=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2}\\\\x=\dfrac{-3-\sqrt{10+10\sqrt{10}}}{2}\notin D

6 0
3 years ago
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