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katen-ka-za [31]
3 years ago
12

In a state lottery 25 balls numbered from 1 to 25 and placed in machine. 6 numbers randomly drawn. And here is the chart what ca

n win a player by buying single lottery ticket:
6 number match $10,000
5 number match $ 5,000
4 number match $ 1000
3 number match $ 5,00
2 number match $ 50
1 number match $ 10
What is probability that player will win $5,000? What is probability to win $50 ?
Mathematics
1 answer:
bonufazy [111]3 years ago
8 0

Answer:

win $5,000: P = 0.0006437

win $50: P = 0.6196

Step-by-step explanation:

To win $5,000, we must have a match of 5 numbers.

So from the 6 numbers, we correcly choose 5 numbers and miss 1 number. The probability of matching or not each of the 6 numbers is:

First number: P = 6/25

Second number: P = 5/24

Third number: P = 4/23

Fourth number: P = 3/22

Fifth number: P = 2/21

Sixth number: P = 19/20 (wrong number)

As the 5 correct numbers can be any of the 6, we also have to multiply the probabilities by a combination of 6 choose 5:

c(6,5) = 6!/5! = 6

So the final probability is:

P = 6 * (6/25) * (5/24) * (4/23) * (3/22) * (2/21) * (19/20) = 0.0006437

To find the probability of winning $50, we can do the same steps above, and we need to correcly match 2 numbers, so we have that:

First number: P = 6/25

Second number: P = 5/24

Third number: P = 22/23 (wrong number)

Fourth number: P = 21/22 (wrong number)

Fifth number: P = 20/21 (wrong number)

Sixth number: P = 19/20 (wrong number)

As the 2 correct numbers can be any of the 6, we also have to multiply the probabilities by a combination of 6 choose 2:

c(6,2) = 6!/(4!*2!) = 6*5/2 = 15

So the final probability is:

P = 15 * (6/25) * (5/24) * (22/23) * (21/22) * (20/21) * (19/20) = 0.6196

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I am thinking of two numbers. The difference of the two numbers is 36. Their sum is 286. What are the two numbers I am thinking
Diano4ka-milaya [45]
Let's call the two numbers a and b. So we know that the difference of the two numbers is 36:

a - b = 36

And we know that their sum is 286:

a + b = 286

We can use either of these equations to solve for one of the variables in terms of the other variable. Let's use the first and solve for a:

a - b = 36

a = 36 + b

Now we plug this into the other equation and solve for b there:

(36 + b) + b = 286 

36 + 2b = 286

2b = 250

b = 125
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Leno4ka [110]
-3,7) yes I am pretty sure that’s the answer
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Matsu wants to measure the dimensions of her vegetable garden. Which unit of measurement should she use to eliminate the need to
Sati [7]
The complete question is
<span>Matsu wants to measure the dimensions of her vegetable garden. Which unit of measurement should she use to eliminate the need to write the values in scientific notation?
inches
feet
cups
tons

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</span><span>is a measure of length used for small dimensions
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8_murik_8 [283]

Answer:

The answer to your question is given below.

Step-by-step explanation:

To which of the above expression is a sum or difference of cube, or not a sum or difference of cube, we shall do the following simplification:

Note: The Cube root of a particular number is simply a multiplication of an identical number in three places.

64x³ – 216

64 has a cube root of 4 and 216 has a cube root of 6. Therefore, the above expression can be written as:

4³x³ – 6³

(4x)³ – 6³

64x³ – 216 = (4x)³ – 6³

Therefore, 64x³ – 216 can be expressed as a difference of cube.

8x^9 + 27

8 has a cube root of 2, x^9 has a cube root of x³ and 27 has a

cube root of 3. Therefore, the above expression can be written as:

2³(x³)³ + 3³

(2x³)³ + 3³

8x^9 + 27 = (2x³)³ + 3³

8x^9 + 27 can be expreessed as a sum of cube

x³ + 125

125 has a cube root of 5. Therefore, the above expression can be written as:

x³ + 5³

x³ + 125 = x³ + 5³

x³ + 125 can be expressed as a sum of cube

36x³ + 121

36 and 121 has no cube root. Therefore, the above expression is not a sum or difference of cube.

x^6 – 16

x^6 has a cube root of x² and 16 has no cube root. Therefore, the above expression is not a sum or difference of cube.

Summary:

Sum or Difference of cubes

64x³ – 216

8x^9 + 27

x³ + 125

Not a Sum or Difference of cubes

36x³ + 121

x^6 – 16

5 0
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Translate the following inequality into written language. 5x-6&lt;14
Scrat [10]
Five x minus six is less than fourteen
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