Question

What is the slope of a line perpendicular to the line whose equation is 12x+2y=-1212x+2y=−12. Fully reduce your answer.

Answer 1

Answer:

In this case the slope of a line perpendicular to the line whose equation is 12x+2y=-12 will be $\frac{1}{6}$

Step-by-step explanation:

A line has the form:

y = m * x + b

where:

• m is the slope of the line.
• b is Y-intercept. This is the value of y where the line crosses the y-axis.

In this case, the line has the form 12*x+2*y=-12

First, you must isolate the variable "y", in order to arrive at the form of the line detailed above:

12*x+2*y=-12

2*y= -12 -12*x

y= (-12 -12*x)÷2

y= (-12)÷2 -(12÷2)*x

y= -6 -6*x

In this case: the slope is -6 and the Y-intercept is -6.

Two lines are perpendicular when they form four equal 90º angles. For two lines to be perpendicular, they must have their slopes inverse and changed sign.

Then, in this case the slope of a line perpendicular to the line whose equation is 12x+2y=-12 will be $\frac{1}{6}$