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kramer
3 years ago
9

What is the slope of a line perpendicular to the line whose equation is 12x+2y=-1212x+2y=−12. Fully reduce your answer.

Mathematics
1 answer:
natali 33 [55]3 years ago
7 0

Answer:

In this case the slope of a line perpendicular to the line whose equation is 12x+2y=-12 will be \frac{1}{6}

Step-by-step explanation:

A line has the form:

y = m * x + b

where:

  • m is the slope of the line.
  • b is Y-intercept. This is the value of y where the line crosses the y-axis.

In this case, the line has the form 12*x+2*y=-12

First, you must isolate the variable "y", in order to arrive at the form of the line detailed above:

12*x+2*y=-12

2*y= -12 -12*x

y= (-12 -12*x)÷2

y= (-12)÷2 -(12÷2)*x

y= -6 -6*x

In this case: the slope is -6 and the Y-intercept is -6.

Two lines are perpendicular when they form four equal 90º angles. For two lines to be perpendicular, they must have their slopes inverse and changed sign.

Then, <u><em>in this case the slope of a line perpendicular to the line whose equation is 12x+2y=-12 will be </em></u>\frac{1}{6}<u><em /></u>

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3ab+5b-6

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Read 2 more answers
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meriva

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-4,\ -1) and \left(\dfrac{1}{2},\ 3\right).

Substitute:

m=\dfrac{3-(-1)}{\frac{1}{2}-(-4)}=\dfrac{4}{4\frac{1}{2}}=\dfrac{4}{\frac{9}{2}}=4\cdot\dfrac{2}{9}=\dfrac{8}{9}\\\\y-(-1)=\dfrac{8}{9}(x-(-4))\\\\y+1=\dfrac{8}{9}(x+4)

The standard form: Ax + By = C

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3 years ago
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Vertex: (-2,1)

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3 years ago
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