All categories

2 years ago

Why isnt 16:14 equivlant to 64:60

Mathematics

1 answer:

nordsb [41]2 years ago

4 0

Answer:

The scalar used does not exist in the real number system.

Step-by-step explanation:

The ratio 16:14 is not equivalent to the ratio 64:60 because the scalar used does not exist in the real number system.

Note, that the ratio 64:60 can be scaled down by 4 to be the ratio 16:15, which is not the ratio 16:14.

In order to scale 64:60 to 16:14 or vise versa, you'd have to use a number that simply does not exist in the real number system.

Cheers.

You might be interested in

Which angle is in standard position

Readme [11.4K]

Answer:

The bottom one

Step-by-step explanation:

its vertex is located at the origin and one ray is on the positive x-axis

4 0

3 years ago

Read 2 more answers

A recipe for muffins calls for 3⁄5 of a cup of sugar and 4 cups of flour. If you want to make a bigger batch, using 5 cups of fl

Wittaler [7]

Answer:

Step-by-step explanation:

3 0

3 years ago

Please help step by step

TEA [102]

Answer:

i have made it in above picture

6 0

3 years ago

How much is 3/4 cup & 3/4 cup =

Anarel [89]

3/4 of a cup plus 3/4 of a cup equals one and a half cups 3/4 cup plus 1/4 equals one cup and that leaves 1.3 cup so answer is one and a half cups

6 0

2 years ago

Read 2 more answers

2)If triangle RPQ is a right angled triangle at Q. If PQ = 5cm and RQ = 10 cm,find (i) sin ^2 P (ii) cos ^2 R and tan R (iii) si

Scorpion4ik [409]

Answer: (i) 1 (ii) 3/4 , √3/3 (iii) 0 (iv) 1

<u>Step-by-step explanation:</u>

ΔRPQ is 1 30°-60°-90° triangle <em>because RQ = 2PQ</em> , where

∠R = 30°
∠P = 90°
∠Q = 60°

(i) sin² (90°) = 1² = 1

$\text{(ii)}\ \cos ^2(30^o)= \bigg(\dfrac{\sqrt3}{2}\bigg)^2=\dfrac{3}{4}$

$.\quad \tan (30^o)=\dfrac{1}{\sqrt3}\bigg=\dfrac{\sqrt3}{3}$

(iii) sin (90°) × cos (90°) = 1 × 0 = 0

(iv) sin² (90°) - cos² (90°) = 1² - 0² = 1

5 0

3 years ago