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Aleksandr-060686 [28]
3 years ago
5

Solve x^2 + 6x + 4=0?

Mathematics
1 answer:
kati45 [8]3 years ago
4 0
You need to use the quadratic formula for this question.
\frac{-b+- \sqrt{b^2-4ac} }{2a}
In your equation, a is 1, b is 6, and c is 4. (I couldn't find a plus minus sign, so that's what the +- means, sorry if there's confusion.)
Sub those into the quadratic formula, and 
\frac{-6+- \sqrt{(6)^2-4(1)(4)} }{2(1)}
For the first answer, we should get 
x1=-0.7639, when you add the √6^2-4(1)(4)
For the second answer, we get
x2=-5.2361 when we subtract the √6^2-4(1)(4)
Therefore, the x values that make this equation equal to 0 should be approximately -0.7639 and -5.2361.
The more specific answers are
x1= -3+√5 and x2=-3-√5.

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The two circles shown above have radii of 8 in. and 2 in.
algol [13]

Answer:

1/4

Step-by-step explanation:

For the first circle 2 x 2in = 4 to find diameter

4 x 3.14 = 12.56

6in x 2 = 12

12 x 3.14 = 37.68

simplify

12.56/37.68

6.28/18.84

3.14/9.42

So the answer is 1/4 since 3.14 x 2 = 6.28

Also since the radius is 2 times longer

3 0
3 years ago
Read 2 more answers
Olivia finished a race in 40.64 seconds. Patty finished the race in 40.39 seconds. Miguel finished the race in 41.44 seconds. Ch
Reika [66]
Patty because she has the lowest time out of them all. From least to greatest Patty would be the least with her time being shorter than the rest
8 0
3 years ago
KN bisects ZJKM. If mZNKJ = 7x-9 and<br> m2JKM = x + 3, find m2JKN.
BaLLatris [955]

Answer:

Step-by-step explanation:

7x - 9 = x + 3

6x - 9 = 3

6x = 12

x = 2

7(2) - 9 + 2 + 3

14 - 9 + 5

5 + 5 = 10

5 0
3 years ago
What are the lengths of DE and EF. Answer with supporting work:
nataly862011 [7]
The length of DE is 39 and the length of EF is 36 because we can see from side AC and DF that triangle DEF is just triangle ABC dilated by 3.
5 0
3 years ago
How many ways can a person toss a coin 13 times so that the number of heads is between 7 and 10 inclusive?
maks197457 [2]

Answer:

4004

Step-by-step explanation:

The number of combinations of choosing r objects from a group of n is nCr.

So the number of ways to get 7, 8, 9, or 10 heads from 13 coin tosses is:

₁₃C₇ + ₁₃C₈ + ₁₃C₉ + ₁₃C₁₀

= 1716 + 1287 + 715 + 286

= 4004

3 0
3 years ago
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