Answer:
a) All of them are out of charge = 9.31x10⁻¹⁰
b) 20% of them are out of charge = 5.529x10⁻⁴
Step-by-step explanation:
This problem can be modeled as a binomial distribution since
There are n repeated trials and all of them are independent of each other.
There are only two possibilities: battery is out of charge and battery is not out of charge.
The probability of success does not change with trial to trial.
Since it is given that it is equally likely for the battery to be out of charge or not out of charge so probability of success is 50% or 0.50
P = 0.50
1 - P = 0.50
a) All of them are out of charge?
Probability = nCx * P^x * (1 - P)^n-x
Probability = ₃₀C₃₀(0.50)³⁰(0.50)⁰
Probability = 9.31x10⁻¹⁰
b) 20% of them are out of charge?
0.20*30 = 6 batteries are out of charge
Probability =₃₀C₆(0.50)²⁴(0.50)⁶
Probability = 5.529x10⁻⁴
What are you converting it to/from?
Answer:
Papi
Step-by-step explanation:
Answer:
1:44
Step-by-step explanation:
You can subtract 32 minutes from 2:32 to get 2:00.
Since you only subtracted 32, subtract 16 (16+32=48) from 60, since 60 minutes is one hour, to get 1:44
Answer:
<h2>9 12/25.</h2>
Step-by-step explanation:
9.48 as a mixed number in simplest form:
<em><u>948/100</u></em>
<em><u>948/100= 948 ÷ 4/100 ÷ 4</u></em>
<em><u>948/100= 948 ÷ 4/100 ÷ 4= 237/25</u></em>
<em><u>948/100= 948 ÷ 4/100 ÷ 4= 237/25= 9 12/25</u></em>
<u>9 12/25 is the mixed number.</u>
