The answer is b. Thank you
X intercept is when y and z=0
yinter cept is when x and z =0
zintercept is when x and y =0
set to zero and solve
xint
-4x+6(0)-5(0)=60
-4x=60
divide -4
x=-15
xint is (-15,0,0)
ying
-4(0)+6y-5(0)=60
6y=60
divide by 6
y=10
yint is (0,10,0)
zint
-4(0)+6(0)-5z=60
-5z=60
divide by -5
z=-12
zint is (0,0,-12)
xint is (-15,0,0)
yint is (0,10,0)
zint is (0,0,-12)
Ok first you have to multiply and get scammed
Answer:
minimum -45, maximum 32
Step-by-step explanation:
C=4x-3y
x≥0, y≥4, x+y≤15
Maximum value of C can be achieved at max x and min y
Minimum value of C can be achieved at min x and max y
So answer is minimum -45, maximum 32
Answer:
Step-by-step explanation:

Use the order of operations.
Note: PEMDAS or BODMAS stands for:
<u>PEMDAS</u>
- <u>Parentheses</u>
- <u>Exponents</u>
- <u>Multiply</u>
- <u>Divide</u>
- <u>Add</u>
- <u>Subtract</u>
<u>BODMAS</u>
- <u>Brackets</u>
- <u>Order</u>
- <u>Divide</u>
- <u>Add</u>
- <u>Subtract</u>
<u>First, do parentheses.</u>
3+6*(5+4)÷3-7
(5+4)=9

<u>Do multiply and divide.</u>
6*9=54
54/3=18
<u>Then, rewrite the problem down.</u>

<u>Add.</u>



- <u>Therefore, the correct answer is "C. 14".</u>
I hope this helps, let me know if you have any questions.