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skad [1K]
2 years ago
13

A class is divided into 4 groups. A bag contains pieces of paper that are red, blue, green, and yellow. For every blue- or green

-colored piece of paper, there are 2 red- and 2 yellow-colored pieces of paper. The students are asked to pick a piece of paper to be put into a particular colored group. What is the probability that the first student will randomly pick a red-colored piece of paper or a blue-colored piece of paper? What additional information would be required to solve the problem? A. the dimensions of the bag B. the number of students in the class C. the sum of the number of green and yellow pieces of paper D. the number of students present in class on that day
Mathematics
1 answer:
Alexus [3.1K]2 years ago
8 0

Answer:

C

Step-by-step explanation:

A has nothing to do with the paper inside and B and D don't matter bc its the first student

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Ne4ueva [31]

Answer:

1/2 of an hour

Step-by-step explanation:

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3 0
3 years ago
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If mCDF = (3x + 14), mFDE = (5x - 2), and mCDE = (10x – 18)", find each measure.
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Step-by-step explanation:

Given mCDF = (3x + 14), mFDE = (5x - 2), and mCDE = (10x – 18)", then the expression mCDE = mCDF+mFDE is true.

To get x, we will substitute the given angles into the formula as shown;

(10x – 18) =  (3x + 14)+ (5x - 2)

10x-18 = 3x+5x+14-2

10x-18 = 8x+12

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For mCDF:

mCDF = 3x + 14

mCDF = 3(15)+ 14

mCDF = 45+14

mCDF = 59°

For mFDE:

mFDE = (5x - 2)

mFDE = 5(15) - 2

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For mCDE:

mCDE = (10x – 18)

mCDE = 10(15) - 18

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mCDE = 132°

4 0
3 years ago
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The steps are as following :

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Step 4 [simplify the equation]: (x^2 − 10x + 25) + (y^2 + 12y + 36) = 64.

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Step 6 [identify the center and radius]: Center = (5, −6) Radius = 8.

<h3>Step 6 is incorrect.</h3><h3>The center should be (5,-6).</h3><h3> Replace − 5 with + 5 and replace + 6 with − 6.</h3>
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Answer:

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