20 POINTS!! EASY QUESTION! WILL MARK BRAINLIEST!! READ THE INFO! THEN FILL IN THE BLANKS!

2 answers:

8 0

To find the unit rate in cost per hour, you will write the amount of money over the total time for each class. Then divide the cost by the time to find the unit rate.

New Steps: $7.50/1.5 hours = $5 per hour

Stepping High: $6.50/1.25 hours = $5.20 per hour

salantis [7]2 years ago

3 0

Answer:

To find the unit rate in cost per hour, you will write the amount of money over the total time for each class. Then divide the cost by the time to find the unit rate.

New Steps: $7.50/1.5 hours = $5 per hour

Stepping High: $6.50/1.25 hours = $5.20 per hour

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(PLEASE ANSWER: TIMED)The intensity, or loudness, of a sound can be measured in decibels (dB), according to the equation I(dB)=1

Mrac [35]

For this case we have the following equation:
$l(dB) = 10log( \frac{l}{lo} )$
We must replace the following value in the equation:
$l = 10^8lo$
Substituting we have:
$l(dB) = 10log( \frac{10^8lo}{lo} )$
Simplifying the given expression we have:
$l(dB) = 10log(10^8)$
Then, using logarithm properties in base 10, we can rewrite the expression:
$l(dB) = 10(8)$
Finally, making the product, the result is:
$l(dB) = 80$
Answer:
$l(dB) = 80$
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