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babunello [35]
2 years ago
8

mitzi has a rectangular swimming pool. she fills it with water to a depth of 5 feet. the water has a volume of 1200 cubic feet.

draw a rectangle that represents the possible dimensions of the swimming pool

Mathematics
2 answers:
ANTONII [103]2 years ago
8 0
To figure out the size of a rectangle that would represent the swimming pool, you will use the formula for volume of a rectangle or prism to solve for the area of the base.

V = Bh
1200 = 5B
B = 240 square feet

To get an area of 240 ft.², you could use the dimensions 10' x 24'. Another possibility would be 8' x 30'.
marusya05 [52]2 years ago
6 0

Answer:

Given: Depth of the swimming pool = 5 feet

Swimming pool is in shape of cuboid

volume of swimming pool = 1200 feet³

Volume of Swimming pool = Area of Base × Height

1200 = Base Area × 5

Base Area = 240 feet²

So, the possible dimension of the rectangle that represent the swimming pool are l = 24 & b = 10  , l = 30 & b = 8 , etc

Figure is attached with one of dimension.

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<u>Solution:</u>

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We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by \left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right) is given by:

\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9

Plugging in the values in formula, we get,

\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}

Hence, the midpoint of the segment is \left(\frac{-9}{2}, \frac{-3}{2}\right)

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Step-by-step explanation:

Given the polynomial

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Divide through by 289

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Half of the coefficient of r is 1/2(102/289)

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