Answer:
<em>51 . 4965 X </em><em><u>1</u></em><em><u>0</u></em><em><u>0</u></em><em>= 5149 . 65</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>correct</em><em> </em><em>answer</em><em>.</em>
The price per ticket, excluding the convenience charge, is $65.
<h3>How to solve for the privce per ticket</h3>
the rush delivery is given as $15.
The total cost of the tickets is said to be put at $352.50
Then the value that we would have for the the 5 tickets wpould be 352.50 - 15 = $337.50.
There is the convenience charge of $2.50 per ticket. This charge is excluded from the convenience charge that is to be paid.
Hence you would have to make the payment of
337.50 - 5*2.50
= 325.
Next we are to solve for the price of the ticket whioch is independent of the convenience charge
= 325 / 5
= $65
Hence the price per ticket is given as 65 dollars
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2x² - 3xy
2(1)² - 3(1)(2)
2(1) - 3(2)
2 - 6
-4
Answer:
Only d) is false.
Step-by-step explanation:
Let
be the characteristic polynomial of B.
a) We use the rank-nullity theorem. First, note that 0 is an eigenvalue of algebraic multiplicity 1. The null space of B is equal to the eigenspace generated by 0. The dimension of this space is the geometric multiplicity of 0, which can't exceed the algebraic multiplicity. Then Nul(B)≤1. It can't happen that Nul(B)=0, because eigenspaces have positive dimension, therfore Nul(B)=1 and by the rank-nullity theorem, rank(B)=7-nul(B)=6 (B has size 7, see part e)
b) Remember that
. 0 is a root of p, so we have that
.
c) The matrix T must be a nxn matrix so that the product BTB is well defined. Therefore det(T) is defined and by part c) we have that det(BTB)=det(B)det(T)det(B)=0.
d) det(B)=0 by part c) so B is not invertible.
e) The degree of the characteristic polynomial p is equal to the size of the matrix B. Summing the multiplicities of each root, p has degree 7, therefore the size of B is n=7.