Question

3. If log 2 =a and log 3=b, the expression 9/32 is equivalent to

Answer 1

Answer:

$\frac{9}{32} = \frac{{10}^{2b} }{{10}^{5a}}$

Step-by-step explanation:

It is given that:

log 2=a and log 3=b

This implies that:

$2 = {10}^{a}$

and

$3 = {10}^{b}$

Now we know that:

$\frac{9}{32} = \frac{ {3}^{2} }{ {2}^{5} }$

We substitute to get:

$\frac{9}{32} = \frac{ ({10}^{b}) ^{2} }{( {10}^{a})^{5} }$

We simplify to get:

$\frac{9}{32} = \frac{{10}^{2b} }{{10}^{5a}}$