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3 years ago

The area of a circle having radius 14 cm is cm. Use * 22 7

Mathematics

1 answer:

DaniilM [7]3 years ago

6 0

Answer:

A=616cm²

Step-by-step explanation:

The question says to use

$\frac{22}{7}$

for pi, now that we know that we proceed like normal and do the formula like this.

$\frac{22}{7} {r}^{2} \\\frac{22}{7} \times 196 \\ = 616$

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Linda read 1/5 of a book on Friday and 2/7 of the book on Saturday. On Sunday she read 5/9 of the remaining pages. What fraction

insens350 [35]

Here, you just want to solve it by finding a common denominator.
1/5+2/7, because she read 1/5 and 2/7 of the book on separate days. The common denominator is 35.
7/35+10/35
=17/35
So that's how much of the book she read before Saturday.
Now it says that on Sunday she read 5/9 of the remaining pages, meaning:
1-17/35 should give us our answer
35/35-17/35=18/35
But since it says she read 5/9 of the remaining pages, we need to multiply 18/35 by 5/9 to get what 5/9ths of 18/35 is.
(18/35)(5/9)=2/7
Therefore she read 2/7ths of the book on Sunday.

3 0

3 years ago

The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi

inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

$\displaystyle\frac{dr}{dt} = -7\text{ inch per second}$

The volume is decreasing at a constant rate.

$\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}$

Instant radius = 99 inch

Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

$V = \displaystyle\frac{1}{3}\pi r^2 h$

Instant volume =

$525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}$

Differentiating with respect to t,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)$

Putting all the values, we get,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131$

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

3 0

3 years ago

Have a Sibling Only Child

alexgriva [62]

Answer: 0.47

Step-by-step explanation:

4 0

3 years ago

Sophie found the volume of the figure below by using the steps shown.

Westkost [7]

Answer: it's C Sophie used the wrong height for the pyramid

It's Right cause I took the test.

Step-by-step explanation:

7 0

3 years ago

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Explain why the mean without the outliner could be a better description of the data set than the mean with the outliner.

lions [1.4K]

Sometimes the outlier, if it's too large, can throw off the mean, making it larger and smaller, so it isn't as accurate

sorry if this doesnt make sense if you need me to explain it more I will

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3 years ago

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