Answer:
may be 13 I hope this is the right answer
Depend on the comparison. if u want to see greater or less then use = < > or the difrent subtract . add if finding the total.
We have to calculate the perimeter of the figure to the nearest tenth of a millimeter. This figure is made of a rectangle and a half of a circle. The first figure has the perimeter: 3 + 6 + 3 = 12 mm. The second figure has the perimeter: 2 * Pi * r / 2 = Pi * r ; and the radius : r = 6/2 = 3 mm. So Pi * 3 = 3.14 * 3 = 9.42. Fimally : 12 + 9.42 = 21.42 or 21.4 to the nearest tenth. Answer: C. 21.4 millimeters<span>. </span>
The arc length of the semicircle is 5π units
<h3>Calculating length of an arc</h3>
From the question, we are to calculate the arc length of the semicircle
Arc length of a semicircle = 1/2 the circumference of the circle
∴ Arc length of a semicircle = 1/2 × 2πr
Arc length of a semicircle = πr
Where r is the radius
From the given information,
r = 5
∴ Arc length of the semicircle = 5 × π
Arc length of the semicircle = 5π units
Hence, the arc length of the semicircle is 5π units
Learn more on Calculating length of an arc here: brainly.com/question/16552139
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Let's use Newton's Law of Universal Gravitation, which is expressed as<span>F=G<span><span><span>(m1</span><span>m2)/</span></span><span>r2</span></span></span>We can find the force of attraction between them. Then, to find the acceleration from<span>F=<span>m1</span><span>a1</span> <span>and</span> F=<span>m2</span><span>a2</span></span>I'll take it you know the equations of motion for constant acceleration. <span>y=<span>1/2</span>a<span>t^2</span></span>
Obviously, as they accelerate towards each other, the radius between
them decreases, meaning the force of gravitation between them increases,
meaning they accelerate faster.